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blagie [28]
3 years ago
9

c) What is moment of inertia? How is it defined (write an equation, explaining all the terms)? What is the parallel axis princip

le for moment of inertia? (if the moment of inertia for a body is I for rotation about an axis that passes through its center of mass, what will be the moment of inertia, Ip, for rotation parallel to that axis? Explain the terms you use in the equation
Physics
1 answer:
ipn [44]3 years ago
4 0

Answer:

Check Explanation

Explanation:

What is moment of inertia?

Mathematically Moment of Inertia I = Mr²

where m = mass of the body

r = distance of body to the rotattinal axis

This is a  quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.

What is the parallel axis principle for moment of inertia?

The theorem of parallel axis states that the moment of inertia of a body about an axis parallel to an axis passing through the centre of mass is equal to the sum of the moment of inertia of body about an axis passing through centre of mass and product of mass and square of the distance between the two axes.

(if the moment of inertia for a body is I for rotation about an axis that passes through its center of mass, what will be the moment of inertia, Ip, for rotation parallel to that axis?

Ip = I + Mα²

Explain the terms you use in the equation

where, α is the distance between two axes (also called the radius of gyration)

I is more moment of inertia about the centre of mass

Ip is the momont of inertia of the rotation parallel to the axis that passes through the centre of mass

M is the mass of the body

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Complete the equation to show the radioactive decay of carbon-14 to nitrogen-14
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Answer:

The beta decay takes place.

Explanation:

The reaction of radioactivity of carbon 14 to nitrogen 14 is

There is a beta decay.  

The reaction is

C_{6}^{14}\rightarrow N_{7}^{14}+\beta _{-1}^{0}+ energy

Here some energy is released in form of neutrino.

7 0
2 years ago
A 3.50 cm tall object is held 24.8 cm from a lens of focal length 16.0 cm. What is the image height?
Mandarinka [93]

Answer:

<h2>6.36 cm</h2>

Explanation:

Using the formula to first get the image distance

1/f = 1/u+1/v

f = focal length of the lens

u = object distance

v = image distance

Given f = 16.0 cm, u = 24.8 cm

1/v = 1/16 - 1/24.8

1/v = 0.0625-0.04032

1/v = 0.02218

v = 1/0.02218

v = 45.09 cm

To get the image height, we will us the magnification formula.

Mag = v/u = Hi/H

Hi = image height = ?

H = object height = 3.50 cm

45.09/24.8 = Hi/3.50

Hi = (45.09*3.50)/24.8

Hi = 6.36 cm

The image height is 6.36 cm

6 0
2 years ago
A speaker vibrates at a frequency of 200 hz what is its period
Norma-Jean [14]

Period = (1) / (frequency)

Period = (1) / (200 per second)  =  0.005 second  =  5 milliseconds

5 0
3 years ago
Read 2 more answers
Lonnie pitches a baseball of mass 0.20 kg. The ball arrives at home plate with a speed of 40 m/s and is batted straight back to
abruzzese [7]

Answer:

B) 20N.s is the correct answer

Explanation:

The formula for the impulse is given as:

Impulse = change in momentum

Impulse = mass × change in speed

Impulse = m × ΔV

Given:

initial speed  = 40m/s

Final speed = -60 m/s (Since the the ball will now move in the opposite direction after hitting the bat, the speed is negative)

mass = 0.20 kg

Thus, we have

Impulse = 0.20 × (40m/s - (-60)m/s)

Impulse = 0.20 × 100 = 20 kg-m/s or 20 N.s

6 0
3 years ago
The mean time between collisions for electrons in room temperature copper is 2.5 x 10-14 s. What is the electron current in a 2
Darya [45]

Answer:

1.87 A

Explanation:

τ = mean time between collisions for electrons = 2.5 x 10⁻¹⁴ s

d = diameter of copper wire = 2 mm = 2 x 10⁻³ m

Area of cross-section of copper wire is given as

A = (0.25) πd²

A = (0.25) (3.14) (2 x 10⁻³)²

A = 3.14 x 10⁻⁶ m²

E = magnitude of electric field = 0.01 V/m

e = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

m = mass of electron = 9.1 x 10⁻³¹ kg

n = number density of free electrons in copper = 8.47 x 10²² cm⁻³ = 8.47 x 10²⁸ m⁻³

i = magnitude of current

magnitude of current is given as

i = \frac{Ane^{2}\tau E}{m}

i = \frac{(3.14\times 10^{-6})(8.47\times 10^{28})(1.6\times 10^{-19})^{2}(2.5\times 10^{-14}) (0.01)}{(9.1\times 10^{-31})}

i  = 1.87 A

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2 years ago
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