Two forces act on a moving object that has a mass of 27 kg. One has a magnitude of 12 N and points due south, while the other ha
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Answer:
0.67m/s²
Explanation:
Given parameters:
Mass of toy = 1.2kg
Force applied = 0.8N
Unknown:
Acceleration = ?
Solution:
According to newton's second law of motion;
Force = mass x acceleration
Now,
Acceleration =
Acceleration = = 0.67m/s²
Answer:
The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N
Explanation:
The details of the given masses having gravitational attractive force between them are;
m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m
The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;
Where;
F = The gravitational force between m₁ and m₂
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
r₂ = 0.1 m + 0.15 m = 0.25 m
Therefore, we have;
The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N