Answer:
Hydrogen bond is a <em>special type of dipole-dipole interaction between the hydrogen atom in a polar bond, such as N-H, O-H, or F-H, and electronegative O,N or F atom</em>. The interaction is written:
A-B . . . B or A-H . . . .A
A and B represent O,N or F; A-H is one molecule or part of a molecule and B is a part of another molecule, and the dotted represents the hydrogen bond. So, hydrogen bond is a type of intermolecular forces (attractive forces between molecules, <u>NOT</u> between atoms of the same molecule), and only a few elements can participate on hydrogen bond formation.
<em>Note: dipole-dipole interactions are forces between polar molecules, that is, between molecules that possess dipole moments. </em>
Answer:
A I believe this is the answer I do not know look at the picture I attached
CO+2 H2=CH3OH
2.85 mol Co x (2mol H2/1 mol Co)=5.70 mol just concert to grams
5.70 mol H2 x (2 g H2/1 mol H2) =11.40 grams of H2
Answer:
These questions bruh. Lol
Explanation:
Idek what to say
Correct Answer: option <span>(1) Mn(s)
Reason:
The </span><span>spontaneity of electrochemical cell, depends on the it's Eo value. Electrochemical cells with positve Eo are spontanous and vice-versa.
</span>
In present case, the Eo of half-cell of interest are as follows:
Eo Zn2+/Zn = <span>-0.763v
</span>Eo Mg2+/Mg = 2.37v
Eo Mn2+/Mn = -1.18v
Therefore, Eo cell (with Zn as one of the half-cell) = Eo Zn2+/Zn - Eo Mn2+/Mn
= -0.763 - (-1.18)
= 0.417v
On other hand, Eo cell (with Mg as one of the half-cell) = Eo Mg2+/Zn - Eo Mn2+/Mn
= -2.37 - (-1.18)
= -1.19v
Thus, Mn(s) <span>metal will spontaneously react with Zn2+(aq), but will not spontaneously react with Mg2+(aq)</span>