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bixtya [17]
3 years ago
11

What are precautions to be taken when doing titrations? A-Make sure to always vigorously shake that flask after every drop if th

e end point is still unknown. It may be that the remaining volume of the titrant needed to reach the end point is just adhering on the wall. This is to ensure accuracy. B-The amounts of solid and liquid should be weighed and pipetted with high accurac This is because all the data that will be produced will mainly depend on this. C- If the end point is unknown, dropwise addition of the titrant is recommended. D- Always make sure that the indicator is added. E- All of the above​
Chemistry
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

E

Explanation:

This is because all steps from A-D are important to obtain an accurate result

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How many grams are in 0.36 moles of CCl4
Leviafan [203]

Answer:

We assume you are converting between moles CCl4 and gram. You can view more details on each measurement unit: molecular weight of CCl4 or grams This compound is also known as Carbon Tetrachloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CCl4, or 153.8227 grams.

Explanation:

Hope this helps :)

5 0
3 years ago
Calculate the volume in ) of 0.100 M Na2CO3 needed to produce 1.00 g of CaCO 3 (s) . There is an excess of CaCl 2. What’s the vo
luda_lava [24]

Answer:

100 mL of Na2CO3

Explanation:

We'll begin by calculating the number of mole in 1 g of CaCO3. This can be obtained as follow:

Mass of CaCO3 = 1 g

Molar mass of CaCO3 = 100.09 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 1/100.09

Mole of CaCO3 = 0.01 mole

Next, we shall determine the number of mole of Na2CO3 needed to produce 0.01 mole of CaCO3.

This is illustrated below:

Na2CO3 + CaCl2 —> 2NaCl + CaCO3

From the balanced equation above,

1 mole of Na2CO3 reacted to produce 1 mole of CaCO3.

Therefore, 0.01 mole of Na2CO3 will also react to produce 0.01 mole of CaCO3.

Next, we shall determine the volume of Na2CO3 needed for the reaction as illustrated below:

Mole of Na2CO3 = 0.01 mole

Molarity of Na2CO3 = 0.1 M

Volume of Na2CO3 solution needed =?

Molarity = mole /Volume

0.1 = 0.01 / volume of Na2CO3

Cross multiply

0.1 × volume of Na2CO3 = 0.01

Divide both side by 0.1

Volume of Na2CO3 = 0.01 / 0.1

Volume of Na2CO3 = 0.1 L

Finally, we shall convert 0.1 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.1 L = 0.1 L × 1000 mL / 1 L

0.1 L = 100 mL

Thus, 0.1 L is equivalent to 100 mL.

Therefore, 100 mL of Na2CO3 is needed for the reaction.

5 0
3 years ago
Radium decays to form radon. *x26Ra 222 Rn + He 86 This type of nuclear decay is called​
mestny [16]

Answer: it's alpha decay (α)

Explanation: mass number of mother nucleus decreases by four and number of protons decreases by two. Smaller nucleus is He-4 nucleus.

3 0
3 years ago
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What do all living things need to survive?
Vinil7 [7]

Answer:

air,water,and food.

Explanation:

Some animals need to obtain their energy from plants.

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