Answer: It is exhibiting retrogade motion.
Answer:
ΔS = +541.3Jmol⁻¹K⁻¹
Explanation:
Given parameters:
Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹
Standard Entropy of C = 5.7Jmol⁻¹K⁻¹
Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹
Standard Entropy of CO = 198Jmol⁻¹K⁻¹
To find the entropy change of the reaction, we first write a balanced reaction equation:
Fe₂O₃ + 3C → 2Fe + 3CO
To calculate the entropy change of the reaction we simply use the equation below:
ΔS = ∑S
- ∑S
Therefore:
ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1
ΔS = +541.3Jmol⁻¹K⁻¹
Out of the choices given, the part of the atom that forms chemical bonds are the outermost electrons. The correct answer is B.
One can tell by looking at the titration curve of an acid and base whether the acid used is a strong acid or a weak acid. For a titration of a strong acid and a strong base, the pH at the equivalence point will be neutral, that is, pH 7. If the titration involves a weak acid and a strong base, the pH at the equivalence point will not be neutral, the solution will be basic at the equivalence point.