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Svetlanka [38]
2 years ago
7

John’s solution to an equation is shown below.

Mathematics
1 answer:
g100num [7]2 years ago
8 0
C would be the correct option
You might be interested in
Angela ordered 2 glass paperweights. The volume of each paperweight is 5 cubic inches, and the density of the glass is 1.5 ounce
Katarina [22]

Answer:

(2\times 5)\times 1.5

Step-by-step explanation:

Since, according to associative property of multiplication,

a(bc) = (ab)c,

Where a, b and c are any real numbers,

Here, the given expression,

2 × ( 5 × 1.5 ),

By applying the associative property of multiplication,

( 2 × 5 ) × 1.5,

Hence, the appropriate expression in the first box is '(2×5)'

And, the appropriate number in the second box is '1.5'.

8 0
3 years ago
CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU
sammy [17]
For this do 5/8-1/2!! in order to do this, find the common denominator. this one is 16, so do: 10/16-8/16, and simplify!
5 0
3 years ago
Read 2 more answers
A research firm tests the miles-per-gallon characteristics of three brands of gasoline. Because of different gasoline performanc
Anni [7]

Answer:

A.) At α = 0.05, is there a significant difference in the mean miles-per-gallon characteristics of the three brands of gasoline.

B.)<u><em>The advantage of attempting to remove the block effect is</em></u>

The completely randomized designs does not prove that H0 is incorrect only that it cannot be rejected.

Step-by-step explanation:

<em><u /></em>

<em><u>Using Two-way ANOVA method</u></em>

Given problem

<em><u>Observation              I          II       III          Row total (xr)</u></em>

A                              18 21 20            59

B                            24 26 27             77

C                            30 29 34             93

D                            22 25 24            71

<u>E                            20 23 24           63                      </u>

Col total (xc)             114 124 129        367

∑x²=9233→(A)

∑x²c/r

=1/5(114²+124²+129²)

=1/5(12996+15376+16641)

=1/5(45013)

=9002.6→(B)

∑x²r/c

=1/3(59²+77²+93²+71²+67²)

=1/3(3481+5929+8649+5041+4489)

=1/3(27589)

=9196.3333→(C)

(∑x)²/n

=(367)²/15

=134689/15

=8979.2667→(D)

Sum of squares total

SST=∑x²-(∑x)²/n

=(A)-(D)

=9233-8979.2667

=253.7333

Sum of squares between rows

SSR=∑x²r/c-(∑x)²/n

=(C)-(D)

=9196.3333-8979.2667

=217.0667

Sum of squares between columns

SSC=∑x²c/r-(∑x)²/n

=(B)-(D)

=9002.6-8979.2667

=23.3333

Sum of squares Error (residual)

SSE=SST-SSR-SSC

=253.7333-217.0667-23.3333

=13.3333

<u>ANOVA table</u>

Source                 Sums         Degrees      Mean Squares

of Variation       of Squares   of freedom

<u>                               SS                 DF              MS       F p-value</u>

B/ w     SSR=217.0667              4 MSR=54.2667    32.56 0.0001

rows

B/w     SSC=23.3333         c-1=2 MSC=11.6667        7 0.01

columns

<u>Error (residual)SSE=13.3333 (r-1)(c-1)=8 MSE=1.6667                  </u>

<u>Total SST=253.7333 rc-1=14                                                        </u>

Conclusion:

<u> 1. F for between Rows</u>

The critical region for F(4,8) at 0.05 level of significance=3.8379

The calculated F for Rows=32.56>3.8379

Therefore H0 is rejected

<u>2. F for between Columns</u>

The critical region for F(2,8) at 0.05 level of significance=4.459

We see that the calculated F for Colums=7>4.459

therefore H0 is rejected,and concluded that there is significant differentiating between columns

<u><em>Part B:</em></u>

To analyze the data for completely  randomized designs click on anova two factor without replication  in the data analysis dialog box of the excel spreadsheet.

The following table is obtained

Source DF             Sum                  Mean           F Statistic

<u>                 (df1,df2)    of Square (SS) Square (MS)                    P-value</u>

Factor A       1 1496.5444 1496.5444 769.6514          0.001297

Rows

Factor B -     2 19.4444           9.7222               5                  0.1667

Columns

Interaction

AB               2    3.8889   1.9444        0.1013         0.9045

<u> Error     12   230.4            19.2                                           </u>

<u>Total 17 1750.2778 102.9575                                                         </u>

<u />

<u>Factor - A- Rows</u>

Since p-value < α, H0 is rejected.

<u>Factor - B- Columns</u>

Since p-value > α, H0 can not be rejected.

The averages of all groups assume to be equal.

<u>Interaction AB</u>

Since p-value > α, H0 can not be rejected.

<u><em>The advantage of attempting to remove the block effect is</em></u>

The completely randomized designs does not prove that H0 is incorrect only that it cannot be rejected.

3 0
2 years ago
How many odd numbers are in 10 to 50?
dlinn [17]

Answer:

20

Step-by-step explanation:

11,13,15,17,19,21,23,25,27,29,31,33,35,37,39,41,43,45,47,49

3 0
2 years ago
How many mL of medication are needed to last 10 days if the dose of medication is 2.5 tsp TID (three times a day)?
rjkz [21]

Answer:

369.7 mL of medication

Step-by-step explanation:

How many mL of medication are needed to last 10 days if the dose of medication is 2.5 tsp TID (three times a day)?

From the above question,

The dosage of the medication =

2.5 tsp 3 times a day

= 2.5 × 3 = 7.5 tsp per day.

Since

1 day = 7.5 tsp

10 days = x tsp

Cross Multiply

x = 10 × 7.5 tsp

x = 75 tsp of medication for 10 days.

Step 2

It is important to note that:

1 tsp = 4.929 mL

75 tsp = x mL

Cross Multiply

x = 75 × 4.929 mL

x = 369.669 mL of medication

Approximately = 369.7 mL of medication

7 0
2 years ago
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