Answer:
See below
Explanation:
Vertical component of initial velocity = 200 sin 35° = 114.72 m/s
then use position formula a = 9.81 m/s^2
0 = 300 + 114.72 t - 1/2 (9.81)(t^2)
use quadratic formula with a = - 4.905 b = 114.72 c = 300
to find t = <u>25.76 seconds </u>
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To find the range
( horizontal distance the projectile lands from launch point)
Horizontal component of initial velocity 200 cos 35 = 163.83 m/s
( it flies horizontally at this speed for <u>25.76 seconds <==found above</u>)
163.83 m/s * 25.76 s = <u>4220.3 meters</u>
Answer:
The angular acceleration is same at all the points in the body.
Option (D) is correct.
Explanation:
Given:
When a rigid body rotates about a fixed axis, all the points in the body have the same,
For finding which quantity is same we use pure rotational concept,

Where
angular frequency,
radius of rigid body
When a rigid body rotates about a fixed axis angular velocity of all the points in the body are same.
But the tangential speed, tangential acceleration, linear displacement, and centripetal acceleration depend on the position of the points and hence they are not the same.
Therefore, the angular acceleration is same at all the points in the body.
Answer:
Thermosphere
temperature continue to rise up to 1500*C
Ionosphere
Mesosphere
temperature falls to -93*C
Stratosphere
protective ozone layer
UV radiation causes temperature to rise
Troposphere
78% nitrogen, 21% oxygen
temperature drops from 17 to -52*C
Explanation:
Answer:
Flow rate 2.34 m3/s
Diameter 0.754 m
Explanation:
Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.
The area at the well head is

So the volume flow rate along the pipe is

We can use the similar logic to find the cross-section area at the refinery

The radius of the pipe at the refinery is:



So the diameter is twice the radius = 0.38*2 = 0.754m