Answer:
31-40 m/s
Explanation:
The kinetic energy of an object is given by :
m is mass of the object
v is velocity
If mass of an object is constant, its kinetic energy depends only on velocity. It means if the velocity is more, it will have maximum kinetic energy. For the interval of 31-40 m/s, the kinetic energy of the object is maximum.
Answer:
θ = 33.54 rad
Explanation:
This is a circular motion exercise
θ= θ₀ + w₀ t + ½ α t²
suppose that for t = 0 the body is at its initial point θ₀ = 0 and from the graph we see that the initial angular velocity w₀ = -9.0 rad / s
we look for the angular acceleration,
α =
from the graph taken two points
α =
α = 3 rad / s²
we substitute in the first equation
θ = 0 -9 t + ½ 3 t²
the displacement is requested for t = 8.6 s
θ = = -9 8.6 + 3/2 8.6²
θ = 33.54 rad
Answer:
Thus, the maximum height is 7.35 m.
Explanation:
initial velocity, u = 12 m/s
acceleration due to gravity, g = 9.8 m/s^2
Velocity at maximum height, v = 0 m/s
Let the maximum height is h.
Use third equation of motion