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3 years ago

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Regeneration in man is limited to

1 answer:

12345 [234]3 years ago

5 0

The answer is gn Fertilization

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the weight of an object on earth is 350 newtons. on mars the same object would weigh 134 newtons. what is the acceleration due t

Eddi Din [679]

Mass will remain constant on both planet, let mass of the object be "m".
let x be the <span>acceleration due to gravity on the surface of mars.
Weight of object on earth = m *g , where g is </span><span>acceleration due to gravity on the surface of earth
</span>⇒350 = m * 9.8
⇒m = 350 / 9.8 .............................equation(1)
Weight of object on mars = m * x , where x is acceleration due to gravity on the surface of mars
134 = m * x .............................equation(2)
putting the value of m from equation (1) in equation(2) , we get,
x = (134 * 9.8) / 350
⇒ x = 3.572 m/s²

7 0

4 years ago

A mountain lion jumps to a height of 3.25 m when leaving the ground at an angle of 43.2°. What is its initial speed (in m/s) as

miss Akunina [59]

Recall that

${v_f}^2={v_i}^2+2a\Delta y$

where $v_i$ and $v_f$ are the lion's initial and final vertical velocities, $a$ is its acceleration, and $\Delta y$ is the vertical displacement.

At its maximum height, the lion has 0 vertical velocity, so we have

$0={v_i}^2-2gy_{\rm max}$

where <em>g</em> is the acceleration due to gravity, 9.80 m/s², and we take the starting position of the lion on the ground to be the origin so that $\Delta y=y_{\rm max}-0=y_{\rm max}$ .

Let <em>v</em> denote the initial speed of the jump. Then

$v_i=v\sin(43.2^\circ)=\sqrt{2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(3.25\,\mathrm m)}\implies\boxed{v\approx11.7\dfrac{\rm m}{\rm s}}$

6 0

3 years ago

20 Points available for physics help

Sonja [21]

The second one is correct not sure about the first one sorry

8 0

3 years ago

Read 2 more answers

A football player, with a mass of 69.0 kg, slides on the ground after being knocked down. At the start of the slide, the player

White raven [17]

Answer:

(a) -472.305 J

(b) 1 m

Explanation:

(a)

Change in mechanical energy equals change in kinetic energy

Kinetic energy is given by $0.5mv^{2}$

Initial kinetic energy is $0.5\times 69\times 3.7^{2}=472.305 J$

Since he finally comes to rest, final kinetic energy is zero because the final velocity is zero

Change in kinetic energy is given by final kinetic energy- initial kinetic energy hence

0-472.305 J=-472.305 J

(b)

From fundamental kinematic equation

$v^{2}=u^{2}+2as$

Where v and u are final and initial velocities respectively, a is acceleration, s is distance

Making s the subject we obtain

$s=\frac {v^{2}-u^{2}}{-2a}$ but a=\mu g hence

$s=\frac {v^{2}-u^{2}}{-2\mu g}=\frac {0^{2}-3.7^{2}}{-2*0.7*9.81}=0.996796272\approx 1 m$

7 0

3 years ago

Question 18/55 (2 p.)

Readme [11.4K]

Answer:

the correct answer is C v = 60 cm / s

Explanation:

The speed of a wave is related to the frequency and the wavelength

v = λ f

They indicate that the object performs 20 oscillations every second, this is the frequency

f = 20 Hz

the wavelength is the distance until the wave repeats, the distance between two consecutive peaks corresponds to the wavelength

λ = 3 cm = 0.03 m

let's calculate

v = 20 0.03

v = 0.6 m / s

v = 60 cm / s

the correct answer is C

6 0

3 years ago