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Fynjy0 [20]
3 years ago
11

Which demonstrates conduction?

Physics
2 answers:
ExtremeBDS [4]3 years ago
8 0

cool feet walking across hot pavement

wariber [46]3 years ago
7 0
Cool feet walking across the hot pavement is correct bc they touch or make contact  <span />
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In a simple harmonic motion, when the displacement from the equilibrium position is at its maximum,
Keith_Richards [23]

Answer:

option B

Explanation:

The correct answer is option B

When the displacement in the harmonic motion is maximum then kinetic energy at the maximum point is minimum and the potential energy is maximum at that point.  

So, when the displacement is maximum, spring force magnitude is also maximum because the force is proportional to the displacement and also the magnitude of the acceleration is maximum so, the net force is also maximum.

7 0
3 years ago
a boy runs from his house to school at speed 5m/s on a straight road and returns with speed of 10m/s.The distance between the ho
CaHeK987 [17]

Explanation:

time spent to run from house to school=100/5=20s

time spent to return from school=100/10=10s

average velocity=200m/(10+20)

  • =6.66m/s
3 0
3 years ago
Four satellites are in orbit around the Earth. The heights of their four orbits
slavikrds [6]

The gravitational pull of Earth is stronger in satellite A

6 0
2 years ago
The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?
ch4aika [34]

Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E +  P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

7 0
3 years ago
14. Three identical light bulbs are connected in series, then are disconnected and arranged in parallel. For each of the scenari
Inessa [10]
In order to make things easier to describe and explain, let's call
the resistance of each bulb 'R', and the battery voltage 'V'.

a).  In series, the total resistance is 3R.
In parallel, the total resistance is R/3.
Changing from series to parallel, the total resistance of the circuit
decreases to 1/9 of its original value.

b).  In series, the total current is  V / (3R) .
In parallel, the total current is  3V / R .
Changing from series to parallel, the total current in the circuit
increases to 9 times its original value.

c).  In series, the power dissipated by the circuit is 

                                   (V) · V/3R  =  V² / 3R .

In parallel, the power dissipated by the circuit is

                                   (V) · 3V/R  =  3V² / R .

Changing from series to parallel, the power dissipated by
the circuit (also the power delivered by the battery) increases
to 9 times its original value.

8 0
3 years ago
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