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Fynjy0 [20]
3 years ago
11

Which demonstrates conduction?

Physics
2 answers:
ExtremeBDS [4]3 years ago
8 0

cool feet walking across hot pavement

wariber [46]3 years ago
7 0
Cool feet walking across the hot pavement is correct bc they touch or make contact  <span />
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What is the objective lens?
Monica [59]

Answer:

The objective lens is an optical tool used to focus an image.

Explanation:

The objective lens is an optical tool that collects light emitted by an object under observation and focuses the  rays of light in order to form a real and magnified image  They are used in optical instruments like microscopes, cameras, telescopes, etc. and are also referred as objective or object glasses.

5 0
3 years ago
Consider the minute hand on a clock. (a) Compute the frequency of its motion in cycles per second. State your answer to three si
kicyunya [14]

Answer:

(a)0.0002778

(b)1.16\times10^{-5}

Explanation:

(a) The minute hand has a period of 60 minutes ( or 60 * 60 = 3600 seconds) for 1 circle. Its frequency per second would be

1 / 3600 = 0.0002778

(b) The hour hand has a period of 24 hours ( or 24*60 * 60 = 86400

seconds) for 1 circle. Its frequency per second would be

1 / 86400 = 1.16\times10^{-5}

5 0
3 years ago
Write a collision scenario here. If you choose your own collision, you can have neither, one, or both of the objects break. Be s
OleMash [197]

Answer:

My scenario would be A Car vs. a guard rail on a road.  You have a car that is coming down a Highway at a speed of 43 Mph Miles per hour (69.2018 Kmh)

And it hits a steel guardrail and the car smashes in at the front and the guardrail is only bent while the car has the bumper and the hood along with the headlights and windshield along with the passenger side window break.

Explanation:

This is caused by so much force reacting from one object to another but also depends on molecular density.

5 0
2 years ago
Ngle of a block is 45 degrees. What is the refractive index​
lyudmila [28]
1.6 ??? I hope I’m right
3 0
3 years ago
Calculate curls of the following vector functions (a) AG) 4x3 - 2x2-yy + xz2 2
aleksandr82 [10.1K]

Answer:

The curl is 0 \hat x -z^2 \hat y -4xy \hat z

Explanation:

Given the vector function

\vec A (\vec r) =4x^3 \hat{x}-2x^2y \hat y+xz^2 \hat z

We can calculate the curl using the definition

\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\A_x&X_y&A_z\end{array}\right|

Thus for the exercise we will have

\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\4x^3&-2x^2y&xz^2\end{array}\right|

So we will get

\nabla  \times \vec A (\vec r )= \left( \cfrac{\partial}{\partial y}(xz^2)-\cfrac{\partial}{\partial z}(-2x^2y)\right) \hat x - \left(\cfrac{\partial}{\partial x}(xz^2)-\cfrac{\partial}{\partial z}(4x^3) \right) \hat y + \left(\cfrac{\partial}{\partial x}(-2x^2y)-\cfrac{\partial}{\partial y}(4x^3) \right) \hat z

Working with the partial derivatives we get the curl

\nabla  \times \vec A (\vec r )=0 \hat x -z^2 \hat y -4xy \hat z

6 0
3 years ago
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