All categories

3 years ago

How many electrons are there in potassium’s outer energy level after the bind had formed

Physics

1 answer:

gayaneshka [121]3 years ago

8 0

Answer:

one electron

Explanation:

An atom with potassium has one electron in its outer energy level. This isn't a sturdy outer energy level. Keep in mind that, with majority of the elements a stable outer energy level has 8 electrons. When it blends with iodine, potassium loses an electron from level 4

You might be interested in

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to en

Nina [5.8K]

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

$dl'=3.621*10^{-4}m$

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder is mathematically given as

$dl=\frac{Flo}{yA}$

$dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}$

$dl=1.19064778*10^-^4$

Generally the equation for brass cylinder is mathematically given as

$dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}$

$dl=2.43*10^{-4}$

Therefore Total change in length

$dl'=1.191*10^-^4+(2.43*10^{-4})$

$dl'=3.621*10^{-4}m$

For more information on this visit

brainly.com/question/23379286

3 0

3 years ago

8. You push downward on a box with a force of 750 N. The box is on a flat horizontal surface for which the coefficient of static

natima [27]

Answer:

The mass of the heaviest box you will be able to move with this applied force = 61.4 kg

Explanation:

From the diagram attached, the forces acting on the box include the weight of the box, applied force on the box, normal reaction of the surface on the box and the Frictional force in the opposite direction to the applied force.

For the box to be able to move, the applied force must have a horizontal component that at least matches the Frictional force between the box and the surface. This is the force balance in the horizontal direction.

Resolving the applied force into horizontal and vertical components,

Fₓ = 750 cos 25° = 679.73 N

Fᵧ = 750 sin 25° = 316.96 N

Doing a force balance in the vertical axis,

N = (mg + 316.96)

Frictional force = μN = μ (mg + 316.96)

μ = 0.74, g = 9.8 m/s²

Frictional force = Fᵧ

μ (mg + 316.96) = 679.73

0.74(9.8m + 316.96) = 679.73

7.252m + 234.5504 = 679.73

7.252m = 679.73 - 234.5504 = 445.1796

m = (445.1796/7.252)

m = 61.4 kg

Hope this Helps!!!

6 0

3 years ago

ou are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distanc

alexgriva [62]

Answer:

The value is $d = 31.45 \ m$

Explanation:

Generally the relative speed at which you are moving with respect to the person ahead of you is mathematically represented as

$v_r = v_s - v_c$

substituting 1.05 m/s for $v_c$ and 2.75 m/s for $v_s$

$v_r = 2.75 - 1.05$

=> $v_r = 1.7 \ m/s$

Generally the distance by which the person is ahead of you is mathematically represented as

$d = v_r * t$

substituting 18.5 s for $t$

$d = 1.7 * 18.5$

=> $d = 31.45 \ m$

4 0

3 years ago

1. Consider a circular track with a radius of 200 meters. A runner starts on the east side and runs around the track to a point

ladessa [460]

Answer:

The magnitude of her displacement when at a point diametrically opposite her starting point is 400 meters

After she has returned to her starting point, the magnitude of her displacement is zero

Explanation:

Displacement is a vector quantity defined as the length of the shortest path between the final and the initial points. In other words, displacement can be defined as the distance traveled in a straight line.

From the question,

The circular track has a radius of 200 meters.

The runner starts on the east side to a point diametrically opposite her starting point. The diametrically opposite point is the point at the opposite end of the diameter of the circle.

Hence, her displacement ( that is, the length of the shortest path between her final and her initial points) is the length of the diameter of the circle.

Diameter d, of a circle is given as twice the radius r, of the circle.

That is, d = 2r

Radius r, of the circular track is 200 meters

∴ d = 2r = 2 (200 meters)

d = 400 meters

Hence, her displacement when at a point diametrically opposite her starting point is 400 meters

Now, after she has returned to her starting point, the magnitude of her displacement is zero.

This is because, the length between her final point ( which is the same as her initial point) and her initial point in zero.

7 0

3 years ago

What's the distance over which a wave's shape repeats

gulaghasi [49]

That's called the wave's "wavelength" .

8 0

4 years ago

Read 2 more answers