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Blababa [14]
3 years ago
8

Write the equation for the inverse of the function: y=sinx

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

<h3>b. y=arcsinx</h3>

Step-by-step explanation:

Given the function y = sinx

The equation of its inverse can be gotten by first taking the arcsin of both sides as shown

arcsiny = arcsin(sinx)

The arcsin will cancel out the sin function at the right hand side to have;

arcsiny = x

x = arcsiny

Replacing the variable 'y' with x and 'x' in y in the resulting equation we have;

y = arcsinx

This gives the required inverse.

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(2a+b)^2÷(3b-1) when a= -2 and b=5
WINSTONCH [101]
Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)

3×5 = 15:
(5 - 2×2)^2/(15 - 1)

 | 1 | 5
- | | 1
 | 1 | 4:
(5 - 2×2)^2/14

2 (-2) = -4:
(-4 + 5)^2/14

5 - 4 = 1:
1^2/14

1^2 = 1:

Answer: 1/14
6 0
3 years ago
What is the value of the expression (x^3y^2)^0
Orlov [11]

Answer:

1

Step-by-step explanation:

6 0
4 years ago
Can you write for me some formula of log please? I have a pre-test tomorrow about that
Rasek [7]
Y = log(x-5) + log(x+5)
7 0
3 years ago
Find the pair of numbers whose sum is 68 and whose product is a maximum.
Aleksandr-060686 [28]
34 and 34 I’m pretty sure
6 0
3 years ago
Find the distance from the point (4,2) to the point (0,1).
vagabundo [1.1K]

Answer:

4.123 units

Step-by-step explanation:

Data provided:

Coordinates of point 1 as ( 4 , 2)

and,

Coordinates of point 2 as ( 0 , 1 )

Now,

The distance between the two point whose coordinates are given is calculated using the formula as:

distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

on substituting the values, we get

distance = \sqrt{(0-4)^2+(1-2)^2}

or

distance = \sqrt{(-4)^2+(-1)^2}

or

distance = \sqrt{16+1}

or

Distance = √17 = 4.123 units

6 0
3 years ago
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