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s344n2d4d5 [400]
3 years ago
14

*asap* Explain how waves, energy and matter are related.

Physics
2 answers:
s344n2d4d5 [400]3 years ago
8 0
I think the answer is that all of those are related by transfer.

basiclly all of those transfer stuff from iself to other things.
maw [93]3 years ago
3 0
The amount of energy carried by a wave will create an energy wave which it will turn into matter


Hope This Help

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A billiard ball is dropped from a height of 64 feet. Use the position function s(t) = –16???? 2 + ????0???? + ????0 to answer th
Delicious77 [7]

Answer:

s(t) = -16*t^2 + 64

v(t) = -32*t

a(t) = -32 ft/s^2

v(t) = 64 ft/s ... At impact

Explanation:

Given:-

- The height of the billiard ball t = 0 , h = 64 ft.

- The position function of an object under gravity is given by:

                                    s(t) = -16*t^2 + v_o*t + s_o

Find:-

a. Determine the position function s(t),

b. the velocity function v(t),

c. the acceleration function a(t).

d. What is the velocity of the ball at impact?

Solution:-

- To determine the position function we must initialize our problem and use the given general equation.

- s(t) is the position of the billiard ball from the ground at time t. So when t = 0, then s(t) = h. Hence, we have:

                                  s(t) = s_o = h = 64 ft

- Similarly we know that v_o is the initial velocity of the ball. Since, the ball was dropped we say that the initial velocity v_o = 0. Hence, the position of the ball from ground is given by following expression:

                                  s(t) = -16*t^2 + 64  

- To find the velocity expression v(t) we will take the time derivative of the position expression s(t) as follows:

                                  v(t) = d s(t) / dt

                                  v(t) = -16*2*t + 0

                                  v(t) = -32*t ft/s

- Similarly, the expression for acceleration a(t) is given by the time derivative of the velocity expression v(t) as follows:

                                  a(t) = d v(t) / dt

                                  a(t) = -32*t

                                  a(t) = -32 ft/s^2

- The velocity of ball at impact can be determined by evaluating s(t) = 0 and find the value for time t. Then that time t can be substituted in the velocity expression v(t) for final velocity. Or we could use the following 3rd kinematic equation as follows:

                                 v(t)^2 - 0^2 = 2*a(t)*s_o

                                 v(t)^2 = 2*(32)*(64)

                                 v(t) = 64 ft/s

- The ball has a velocity of 64 ft/s at impact!

6 0
3 years ago
If a net force applied to an object is equal to zero, then the forces that are acting on an object are considered.
hjlf

Answer:

The mass will accelerate. Balanced Forces: When forces are in balance, acceleration is zero. Velocity is constant and there is no net or unbalanced force. A plane will fly at constant velocity if the acceleration is zero.

Explanation:

5 0
3 years ago
Read 2 more answers
Please help don't for get to show work
emmasim [6.3K]
-- Bob covered a distance of (32m + 45m) = 77 meters.

-- His displacement is the straight-line distance and direction
from his starting point to his ending point.

The straight-line distance is

D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters

The direction is the angle whose tangent is (32/45) south of east.

tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.
3 0
3 years ago
-
Sergeeva-Olga [200]

Answer:

(a) 32.5 kgm/s

(b) 32.5 Ns

(c) 10.8 N

Explanation:

The change in momentum can be calculated from the definition of linear momentum:

\Delta p=\Delta (mv)= m \Delta v\\\\\Delta p= (5.00kg)(9.75m/s-3.25m/s)\\\\\Delta p=32.5kgm/s

Then, the change in momentum of the body is of 32.5 kgm/s (a).

Now, from the impulse-momentum theorem, we know that the change in momentum of a body \Delta p is equal to the impulse I exerted to it. So, the impulse produced by the force equals 32.5 kgm/s (or 32.5 Ns) (b).

Finally, since we know the value of the impulse and the interval of time, we can easily solve for the magnitude of the force:

I=F\Delta t\\\\\implies F=\frac{I}{\Delta t}\\\\F=\frac{32.5Ns}{3.0s}\\\\F=10.8N

It means that the magnitude of the force is of 10.8N (c).

8 0
3 years ago
Read 2 more answers
during a _____, a substance mixes with another substance and changes into completely new substances with different properties.
Tatiana [17]

chemical change or chemical reaction

7 0
3 years ago
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