Density: g/mL, kg/cubic meter
Volume: L, teaspoon
Mass: g, MeV/sq. C
Answer:

Explanation:
Given data:
L =2.00 *10^4 m
d = 18*10^4 m
M = 18 *10^6 kg
m_1 = 8*10^6 kg
Gravitational energy is given as

mass per unit length is given as

calculating potential energy







Answer:
2.6 m
Explanation:
The work done by the bird is given by

where
F is the force exerted
d is the distance covered
In this problem, we know:
is the work
is the force
Solving the equation for d, we find the distance covered by the bird:

To develop this problem it is necessary to apply the oscillation frequency-related concepts specifically in string or pipe close at both ends or open at both ends.
By definition the oscillation frequency is defined as

Where
v = speed of sound
L = Length of the pipe
n = any integer which represent the number of repetition of the spectrum (n)1,2,3...)(Number of harmonic)
Re-arrange to find L,

The radius between the two frequencies would be 4 to 5,


Therefore the frequencies are in the ratio of natural numbers. That is

Here f represents the fundamental frequency.
Now using the expression to calculate the Length we have

Therefore the length of the pipe is 1.3m
For the second harmonic n=2, then

Therefore the length of the pipe in the second harmonic is 2.6m