Answer:
I would increase the horizontal velocity or the vertical velocity or both to make the ball go the extra distance to cross the goal line.
Explanation:
In order to increase the horizontal distance covered by the ball, we need to examine the variables involved in the formula of range of projectile. The formula for the range of projectile is given as follows:
R = V₀² Sin 2θ/g
where, g is a constant on earth (acceleration due to gravity) and θ is the angle of ball with ground at the time of launching. The value of θ should be 45° for maximum range. In this case we do not know the angle so, we can not tell if we should change it or not.
The only parameter here which we can increase to increase the range is launch velocity (V₀). The formula for V₀ in terms of horizontal and vertical components is as follows:
V₀ = √(V₀ₓ² + V₀y²)
where,
V₀ₓ = Horizontal Velocity
V₀y = Vertical Velocity
Hence, it is clear from the formula that we can increase both the horizontal and vertical velocity to increase the initial speed which in turn increases the horizontal distance covered by the ball.
<u>Therefore, I would increase the horizontal velocity or the vertical velocity or both to make the ball go the extra distance to cross the goal line.</u>
Question in proper order
The rotational kinetic energy term is often called the <em>kinetic energy </em><em>in</em> the center of mass, while the translational kinetic energy term is called the <em>kinetic energy </em><em>of</em> the center of mass.
You found that the total kinetic energy is the sum of the kinetic energy in the center of mass plus the kinetic energy of the center of mass. A similar decomposition exists for angular and linear momentum. There are also related decompositions that work for systems of masses, not just rigid bodies like a dumbbell.
It is important to understand the applicability of the formula

Which of the following conditions are necessary for the formula to be valid?
a. The velocity vector
must be perpendicular to the axis of rotation
b.The velocity vector
must be perpendicular or parallel to the axis of rotation
c. The moment of inertial must be taken about an axis through the center of mass
Answer:
Option c
Explanation:

The first two conditions are untrue, this is because, you can have rotation in any direction and translation in any direction of any collection of masses. Rotational and translational velocities of masses do not depend on each other
The last statement is true because by definition, the moment of inertia, which is a measure of reluctance, is usually taken about a reference point which is the center of mass
The bus will travel a further 20 m before coming to rest.
<h3>What is acceleration?</h3>
The term acceleration has to do with a change in velocity with time. Now we have;
u = 20 m/s
v = 10 m/s
s = 60 m
Now;
v^2 = u^2 -2as
v^2 - u^2 = -2as
(10)^2 - (20)^2 = - 2 * a * 60
a = (10)^2 - (20)^2/ - 2 * 60
a = 100 - 400/ - 2 * 60
a = 2.5 m/s^2
At that time;
v = 0 m/s
u = 20 m/s
a = 2.5 m/s^2
s = ?
Hence;
u^2 = 2as
s = u^2/2a
s = (20)^2/ 2 * 2.5
s = 400/5
s = 80 m
Hence, the bus will travel a further 20 m before coming to rest.
Learn more about acceleration:brainly.com/question/12550364
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i think the best answer for this question is B)
The answer is B.
This is because both cars are moving at the same speed, but have different velocities due to the different directions they are moving in.