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nordsb [41]
3 years ago
7

An unknown liquid has a mass of 30.70 g and a volume of 52.3 mL. What is the density of the liquid?

Physics
2 answers:
patriot [66]3 years ago
7 0
The answer is 0.58699809 or rounded to the nearest hundredth 0.59 because the formula for density is density=mass/volume.
kolbaska11 [484]3 years ago
6 0

Answer:

de sity=mass÷volume.........

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Which is an example of chemical energy from batteries to electromagnetic ( light ) energy?
TiliK225 [7]

Answer:

B.

Explanation:

The batteries make it so the chemical energy is being passed into the flashlight allowing it to work as designed forming light.

4 0
4 years ago
Could I get help on this question please . My parents won’t help me /:
vovikov84 [41]

Answer:

Tarzan will be moving at 7.4 m/s.

Explanation:

From the question given above, the following data were obtained:

Height (h) of cliff = 2.8 m

Initial velocity (u) = 0 m/s

Final velocity (v) =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 2.8)

v² = 0 + 54.88

v² = 54.88

Take the square root of both side

v = √54.88

v = 7.4 m/s

Therefore, Tarzan will be moving at 7.4 m/s at the bottom.

3 0
3 years ago
A slab of glass 8.0 cm thick is placed upon a printed page. If the refractive index of the glass is 1.5, how far from the surfac
7nadin3 [17]

Answer:

5.3 cm

Explanation:

This question is an illustration of real and apparent distance.

From the question, we have the following given parameters

Real Distance, R = 8.0cm

Refractive Index, μ = 1.5

Required

Determine the apparent distance (A)

The relationship between R, A and μ is:

μ = R/A

i.e.

Refractive Index = Real Distance ÷ Apparent Distance

Substitute values in the above formula

1.5 = 8/A

Multiply both sides by A

1.5 * A = A * 8/A

1.5A = 8

Divide both side by 1.5

1.5A/1.5 = 8/1.5

A = 8/1.5

A = 5.3cm

Hence, the letters would appear at a distance of 5.3cm

8 0
3 years ago
Describe a technology used in space exploration.
Alex777 [14]

Answer:

High speed optical communication technology

To be able to communicate from the space to the earth and from earth to space is one of the most essential features required during space exploration.

Explanation:

Space exploration involves going into the space, beyond the earth's atmosphere. Landing on other planets and studying their details, going into deeper space beyond the planets to discover new cosmic events or structures is all a part of space exploration.

The key to analyse the studies and observations is being able to communicate the data collected, photos taken etc to the launch centers or space centers on earth. The space centers on earth should also be able to communicate with the persons or the satellites in space.

This is made possible using the optical communication technology which involves the use of optical fibers, lasers etc, since high speeds are more efficient during communication

3 0
3 years ago
A proton moves in the negative x-direction through a uniform magnetic field in the negative y-direction what is the direction of
ANEK [815]

A proton travels through a constant magnetic field in the negative y-direction while moving in the negative x-direction. The proton will be subject to a magnetic pull that is directed into the page. Option B is correct.

<h3>What is the right-hand thumb rule?</h3>

Hold a current-carrying conductor in your right hand with your thumb pointing in the direction of the current then wrap your fingers around the conductor and orient them in the direction of the magnetic field lines.

A proton travels through a constant magnetic field in the negative y-direction while moving in the negative x-direction.

The proton will be subject to a magnetic pull that is directed into the page.

Hence, option B is correct.

To learn more about the right-hand thumb rule refer to the link;

brainly.com/question/11521829

#SPJ1

4 0
2 years ago
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