All categories

3 years ago

An unknown liquid has a mass of 30.70 g and a volume of 52.3 mL. What is the density of the liquid?

2 answers:

7 0

The answer is 0.58699809 or rounded to the nearest hundredth 0.59 because the formula for density is density=mass/volume.

kolbaska11 [484]3 years ago

6 0

Answer:

de sity=mass÷volume.........

You might be interested in

Which device will allow you to reduce the voltage from 120 vac to vdc in order to charge a cell phone?

Darina [25.2K]

It should be 4. An alternator

6 0

3 years ago

When you put a pot of water on the stove, the stove transfers thermal energy to the water. As the water gains large

STALIN [3.7K]

Answer:

It releases some of the energy into the atmosphere as hot steam.

Explanation:

8 0

3 years ago

One Newton is equivalent to A. 1 kg/s2 B. 1 kg*m/s C. 1 kg*m/s2 D. 1 kg/s

tiny-mole [99]

Answer:

Explanation:

7 0

3 years ago

If the density of a substance is 5g/cm3 and the volume is 10cm3, determine the mass.

vaieri [72.5K]

Answer:

(5g/cm³)*(10cm³) = 50g

Explanation:

This is just a conversion formula. Easy to find using dimensional analysis.

(5g/cm³)*(10cm³) = 50g

6 0

3 years ago

Read 2 more answers

A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimumcoefficient of static friction

zhenek [66]

Answer:

c. 0.816

Explanation:

Let the mass of car be 'm' and coefficient of static friction be 'μ'.

Given:

Speed of the car (v) = 40.0 m/s

Radius of the curve (R) = 200 m

As the car is making a circular turn, the force acting on it is centripetal force which is given as:

Centripetal force is, $F_c=\frac{mv^2}{R}$

The frictional force is given as:

Friction = Normal force × Coefficient of static friction

$f=\mu N$

As there is no vertical motion, therefore, $N=mg$ . So,

$f=\mu mg$

Now, the centripetal force is provided by the frictional force. Therefore,

Frictional force = Centripetal force

$f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu=\frac{v^2}{Rg}$

Plug in the given values and solve for 'μ'. This gives,

$\mu = \frac{(40\ m/s)^2}{200\ m\times 9.8\ m/s^2}\\\\\mu=\frac{1600\ m^2/s^2}{1960\ m^2/s^2}\\\\\mu=0.816$

Therefore, option (c) is correct.

7 0

4 years ago