All categories

3 years ago

An unknown liquid has a mass of 30.70 g and a volume of 52.3 mL. What is the density of the liquid?

2 answers:

7 0

The answer is 0.58699809 or rounded to the nearest hundredth 0.59 because the formula for density is density=mass/volume.

kolbaska11 [484]3 years ago

6 0

Answer:

de sity=mass÷volume.........

You might be interested in

What effect does an increase in temperature have on viscosity?

Bogdan [553]

Gravitational acceleration aka Weight

3 0

3 years ago

Read 2 more answers

Radon is a radioactive gas found below ground. If a sample of radon occupies 29 mL at 25 oC, what volume will it occupy at 500 K

Valentin [98]

Answer:

48.63 mL

Explanation:

Using Charles's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = 29 mL

V₂ = ?

T₁ = 25 °C

T₂ = 500 K

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25 + 273.15) K = 298.15 K

Using above equation as:

$\frac{29\ mL}{298.15\ K
}=\frac{V_2}{500\ K}$

$V_2=\frac{29\cdot \:500}{298.15}\ mL$

<u>New volume = 48.63 mL</u>

8 0

3 years ago

During an experiment, your teacher gives you two objects: tissue paper and a balloon. You observe that the tissue paper repels t

Galina-37 [17]

Answer:

i think your answer is this: the objects have no interactive with each other.

Explanation:

if you think about it tissue paper doesn't really have a static electrical charge if it does it is very weak so therefore cannot really attract or repel anything.

3 0

3 years ago

Read 2 more answers

Beyond the petition Neptune a field of smaller bodies orbits the Sun.Some scientists think these objects are the remains of mate

Vladimir79 [104]

This is a very valid hypothesis for many reasons. One is that solar systems form from massive amounts of dust, ice, and debris that eventually form into planets and such. This means it is very possible for this 'excess material' if you will to have moved into orbit behind Neptune.

3 0

3 years ago

A straight wire of length 0.62 m carries a conventional current of 0.7 amperes. What is the magnitude of the magnetic field made

anyanavicka [17]

Answer:

Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T

Explanation:

Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :

$B=\frac{\mu_{0}I }{2\pi R }\times\frac{L}{\sqrt{L^{2}+R^{2} } }$ ......(1)

Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.

In this problem,

Current, I = 0.7 A

Length of wire, L = 0.62 m

Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m

Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m

Substitute these values in equation (1).

$B=\frac{4\pi\times10^{-7}\times 0.7 }{2\pi \times0.02 }\times\frac{0.62}{\sqrt{(0.62)^{2}+(0.02) ^{2} } }$

B = 6.99 x 10⁻⁶ T

3 0

3 years ago