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MAXImum [283]
3 years ago
8

A ladder is at rest with Oct upper end against a wall and its lower end on the ground.A worker is about to climb it.When is it m

ore likly to slip
Physics
1 answer:
almond37 [142]3 years ago
5 0

Answer: When the worker is on the top rung

Explanation: When the ladder was initially resting on the wall, the torque from the normal reaction on ladder from the horizontal surface is equal to the torque from the vertical surface on ladder.

The weight of the worker produces a torque which is in the direction of the torque from the normal reaction on ladder, produced by the vertical surface. Therefore for the ladder to stay in rotational equilibrium, the torque on ladder from the normal reaction produced by the horizontal surface must increase.

This increase is possible when the worker is on the lower rung, but as the worker goes high, the magnitude of normal reaction from the vertical surface would increase, thereby increasing the risk of slipping of ladder.

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One gallon of paint covers an area of 25 m2. What is the thickness of the paint on the wall?​
Flura [38]

Answer:

Explanation:

1 gal = 231 in³

231 in³ (2.54³ cm³/in³) = 3,785.411784 cm³

3,785.411784 cm³ (0.01³ m³/cm³) = 0.003785411784 m³

0.003785411784 m³ / 25 m² = 0.00015141647136 m

or approximately 0.15 mm

6 0
2 years ago
The principles of magnetism apply everywhere on earth. What does this tell us about God and His character?
Bas_tet [7]

Answer:

God is omnipresent.

Explanation:

This means God is everywhere and He works where ever we are in the world

3 0
3 years ago
A stunt driver rounds a banked, circular curve. The driver rounds the curve at a high, constant speed, such that the car is just
bagirrra123 [75]

Answer: C

Frictional force

Explanation:

The description of the question above is an example of a circular motion.

For a car travelling in a curved path, the frictional force between the tyres and the road surface will provide the centripetal force.

Since the road is banked, and the cross section of the banked road is constructed like a ramp. The car drives transversely to the slope of the ramp, so that the wheels of one side of the car are lower than the wheels on the other side of the car, for cornering the banked road, the car will not rely only on the frictional force.

Therefore, the correct answer is option C - the frictional force.

5 0
3 years ago
How do the dark lines of an atom''s absorption spectrum relate to the bright lines of its emission spectrum?
tangare [24]

Wouldn't it be neat if an electron falling closer to the nucleus ... emitting a
photon ... actually gave out more energy than it needed to climb to its original
energy level by absorbing a photon !   If there were some miraculous substance
that could do that, we'd have it made.

All we'd need is a pile of it in our basement, with a bright light bulb over the pile,
connected to a tiny hand-crank generator.

Whenever we wanted some energy, like for cooking or heating the house, we'd
switch the light bulb on, point it towards the pile, and give the little generator a
little shove.  It wouldn't take much to git 'er going.

The atoms in the pile would absorb some photons, raising their electrons to higher
energy levels.  Then the electrons would fall back down to lower energy levels,
releasing more energy than they needed to climb up.  We could take that energy,
use some of it to keep the light bulb shining on the pile, and use the extra to heat
the house or run the dishwasher.

The energy an electron absorbs when it climbs to a higher energy level (forming
the atom's absorption spectrum) is precisely identical to the energy it emits when
it falls back to its original level (creating the atom's emission spectrum).

Energy that wasn't either there in the atom to begin with or else pumped
into it from somewhere can't be created there.

You get what you pay for, or, as my grandfather used to say, "For nothing
you get nothing."

3 0
3 years ago
Which describes the changes in visible light moving from red to violet?
Alexxx [7]
The energy increases
5 0
2 years ago
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