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Dmitry [639]
2 years ago
10

Draw the well labelled diagram of thermo flask.​

Physics
1 answer:
DochEvi [55]2 years ago
5 0

Answer:

Here the answer is attached

Explanation:

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Which of the following statements about the
Komok [63]

Answer: the answer is A

Explanation: just did it

8 0
2 years ago
Gold has a density of 19.3 g/cm3. What is the mass of a 5 cm3 block of gold?
Tems11 [23]
Do not forget that mass = <span>volume x density
</span>Mass of 1 cm^3 = Density[/tex]
mass of 2 cm^3 = 19.3 g + 19.3 g = 2*19.3 g
Then eventually we can find <span>mass of 5 cm^3 : = 
</span>19.3 g + 19.3 g+19.3g+19.3g+19.3g= 5*19.3 g
So the answer is D
<span>And that's it. I'm sure it will help.</span>
5 0
2 years ago
In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of t
muminat
<h2><em><u>⇒</u></em>Answer:</h2>

In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.600 m and the acceleration achieved from this position is 1.25 times the acceleration due to gravity, g . How far can they jump? State your assumptions. (Increased range can be achieved by swinging the arms in the direction of the jump.)

Step-by-Step Solution:

Solution 35PE

This question discusses about the increased range. So, we shall assume that the angle of jumping will be  as the horizontal range is maximum at this angle.

Step 1 of 3<

/p>

The legs have an extension of 0.600 m in the crouch position.

So,  m

The person is at rest initially, so the initial velocity will be zero.

The acceleration is  m/s2

Acceleration  m/s2

Let the final velocity be .

Step 2 of 3<

/p>

Substitute the above given values in the kinematic equation  ,

m/s

Therefore, the final velocity or jumping speed is  m/s

Explanation:

3 0
3 years ago
Read 2 more answers
The California sea lion is capable of making extremely fast, tight turns while swimming underwater. In one study, scientists obs
anygoal [31]

Answer:

Acceleration of Sea Lion is 4.41 g

This is 49% of maximum jet acceleration given as a = 9g

Explanation:

As we know that the radius of the circular loop is given as

R = 0.37 m

The speed of the fish is given as

v = 4 m/s

Now the centripetal acceleration of the sea lion is given as

a_c = \frac{v^2}{R}

a_c = \frac{4^2}{0.37}

a_c = 43.2 m/s^2

as we know that

g = 9.8 m/s^2

so we have

a = 4.41 g

Now Percentage of this acceleration wrt maximum jet acceleration is given as

P = \frac{4.41 g}{9g} \times 100

P = 49%

6 0
3 years ago
A student pushes against a wall with a force of 30N. The wall does not move. What amount of force does the wall exert on the stu
True [87]

Answer:

C

Explanation:

they both have to be the same for both to not move

8 0
2 years ago
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