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Andrews [41]
3 years ago
8

a box weighing 155 N is pushed horizontally down the hall at constant velocity. the applied force is 83 n what is the coefficien

t of friction between the box and the floor
Physics
1 answer:
meriva3 years ago
8 0

Answer:

μ = 0.535

Explanation:

On a level floor, normal force = weight.

N = W

Friction force = normal force × coefficient of friction.

F = Nμ

Substitute:

F = Wμ

83 = 155μ

μ = 0.535

Round as needed.

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Calculate the frequencies corresponding to the wavelengths 500.00 nm and 500.10 nm. Use these to check the accuracy of equation
mel-nik [20]

Explanation:

It is given that,

Wavelength, \lambda_1=500\ nm=5\times 10^{-7}\ m

Wavelength, \lambda_2=500.10\ nm=5.001\times 10^{-7}\ m

We need to find the frequencies from corresponding wavelengths. The frequency of the light is given by :

f=\dfrac{c}{\lambda}  

c is the speed of light

Frequency 1,

f_1=\dfrac{c}{\lambda_1}  

f_1=\dfrac{3\times 10^8\ m/s}{5\times 10^{-7}\ m}  

f_1=6\times 10^{14}\ Hz

Frequency 2,

f_2=\dfrac{c}{\lambda_2}  

f_1=\dfrac{3\times 10^8\ m/s}{5.001\times 10^{-7}\ m}  

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3 0
3 years ago
How much min the basketball 1 player play​
Sedbober [7]

Answer:

A professional basketball game depends on the association presiding over the game. An NBA game lasts for 48 minutes whereas FIBA games take 40 minutes. The total time taken to play for any specialized game is over 2 hours 15 minutes. The time includes the time disruptions like fouls, timeouts, and breaks.

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3 0
3 years ago
The charge of an electron is -1.60x10-19 C. A current of 1 A flows in a wire carried by electrons. How many electrons pass throu
faltersainse [42]

Answer: 6.241\times 10^{18} electrons pass through a cross section of the wire each second.

Explanation:

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

Given : Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

To calculate the charge passed we use the equation:

I=\frac{q}{t}

where,

I = current passed = 1 A

q = total charge = ?

t = time required = 1 sec

Putting values in above equation, we get:

1A=\frac{q}{1s}\\\\q=1A\times 1s=1C

When 96500C of electricity is passed , the electrons passed = 6.022\times 10^{23}

1 C of electricity is passed , the electrons passed = \frac{6.022\times 10^{23}}{96500}\times 1C=6.241\times 10^{18}

Hence, 6.241\times 10^{18} electrons pass through a cross section of the wire each second.

4 0
3 years ago
if a weight of 100 lbs is moved through a displacement of 1.2m, how much work was done to move the weight
OLEGan [10]

Answer:

534 j

Explanation:

100 lbs = 45.359 kg

work = F * d

         = 45.359 * 9.81  * 1.2 = ~ 534 j

6 0
2 years ago
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