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3 years ago

In what way are Paul Robeson and Sonia Sotomayor alike?

Chemistry

1 answer:

mart [117]3 years ago

7 0

Answer:

C is the answer.

Explanation:

They are both people of color who were the first to do something in their fields

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QUESTION 1 (POLL)

Airida [17]

Answer:

They stay the same

Explanation:

4 0

3 years ago

Sodium metal (Na) reacts with chlorine gas ( Cl2 ) to produce solid sodium chloride (NaCl).

Fynjy0 [20]

The unbalanced equations are the equations with different atomic numbers on the sides of the reaction. The unbalanced reaction is Na + Cl₂ → NaCl

<h3>What are balanced equations?</h3>

Balanced equations are the chemical reaction representation that has an equal number of the atomic number of the same species on the left and the right side of the reaction.

An unbalanced equation between sodium metal and chloride can be shown as:

Na + Cl₂ → NaCl

The equation is unbalanced as the number of chloride ions is more on the reactant side than the product side.

The balanced reaction will be:

2 Na + Cl₂ 2NaCl

Learn more about balanced equations here:

brainly.com/question/10306791

#SPJ1

3 0

2 years ago

In the game of economics, goods are objects that fulfill peoples needs and ____.

Evgen [1.6K]

Goods are objects that fulfill peoples needs and wants.

4 0

3 years ago

Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe

leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as molarity, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

$c = \frac{n}{V}$

n = moles (unit mol)

V = volume (unit L)

Find the molar mass (M) of potassium hydroxide.

$M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}$

$M_{KOH} = 56.106 \frac{g}{mol}$

Calculate the moles of potassium hydroxide.

$n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}$

$n_{KOH} = 0.25941(9)mol$

Carry one insignificant figure (shown in brackets).

Convert the volume of water to litres.

$V = \frac{500.0mL}{1}*\frac{1L}{1000mL}$

$V = 0.5000L$

Here, carrying an insignificant figure doesn't change the value.

Calculate the concentration.

$c = \frac{n}{V}$

$c = \frac{0.25941(9)mol}{0.5000 L}$

$c = 0.5188(3) \frac{mol}{L}$ <= Keep an insignificant figure for rounding

$c = 0.5188 \frac{mol}{L}$ <= Rounded up

$c = 0.5188M$ <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

7 0

3 years ago

Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi

xenn [34]

Conjugate base of Propanoic acid ( $CH_{3}CH_{2}COOH$ is propanoate where -COOH group gets converted to -CO $O^{1-}$ . The structure of conjugate base of Propanoic acid is shown in the diagram.

The $p^{H}$ above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

$p^{H}$ = $p^{k_{a}$ + log $\frac{[Conjugate base]}{[acid]}$ =4.9+log $\frac{90}{10}$ =5.85

As 90% conjugate base is present, so propanoic acid present 10%.

8 0

4 years ago