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3 years ago

A stable, binary ionic compound exists where the cation (A) has a change twice in magnitude than that of the anion (X)

Chemistry

1 answer:

love history [14]3 years ago

8 0

Answer:

AX₂

Explanation:

Binary compounds:

The compounds which are made up of the atoms of only two elements are called binary compounds.

For example:

The following compounds are binary:

HCl

H₂O

NH₃

HCl is binary because it is composed of only hydrogen and chlorine. Ammonia is also binary compound because it is made up of only two elements nitrogen and hydrogen.

water is also binary because it is also made up of only two elements hydrogen and oxygen.

In given question it is stated that the charge of cation is twice than the anion which means its charge would be +2 thus anionic part will have the charge -1. In neutral compound the positive and negative charges must be equal in magnitude to cancel the effect of each other and make the compound neutral. So, there must be two anionic atom present so that charge becomes -2 and cancel the +2 charge of cationic part. Thus the formula will be,

AX₂

A⁺²X₂⁻²

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A 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O. Find the mass of sulfur in a sample of CaSO4 with a m

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The mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

<h3>How to calculate mass of an element in a compound?</h3>

According to this question, a 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O.

This means that the mass of sulfur in the 10.4g of CaSO4 is 10.4g - (3.06g + 4.89g) = 10.4g - 7.95g = 2.45g

Next, we calculate the percent ratio of each element in the compound; CaSO4.

Ca = 3.06g/10.4g × 100 = 29.42%
S = 2.45g/10.4g × 100 = 23.56%
O = 4.89g/10.4g × 100 = 47.02%

According to this question, a sample of CaSO4 with a mass of 65.8 g is given. The mass of each element in this compound is as follows:

Ca = 29.42/100 × 65.8g = 19.36g
S = 23.56/100 × 65.8g = 15.50g
O = 47.02/100 × 65.8g = 30.94g

Therefore, the mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

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Consider the chemical equations shown here.

vichka [17]

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Now let us derive this equation:

Given equations:

P₄ $_{s}$ + 30₂ $_{g}$ ⇒ P₄0₆ $_{s}$ equation 1;

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To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

P₄0₆ $_{s}$ ⇒ P₄ $_{s}$ + 30₂ $_{g}$ equation 3

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