All categories

3 years ago

Find the mode of the following data:

1 answer:

5 0

C. 16

To find the mode, you find the highest number in the data set, then you subtract the highest number (21) from the lowest number in the data set (4). So the mode would be 16.

You might be interested in

As a promotion, a clothing store draws the name of one of its customers each week. The prize is a coupon for the store. If the w

kompoz [17]

The given formula is f(x) = 20(1.2)^x

The formula is the starting amount multiplied by 1 + the percentage raised to the number of weeks.

A) the percent increase is 20% ( 1.2 in the formula is 1 +20% as a decimal)

B) the original amount is $20

C) for 2 weeks, replace x with 2 and solve:

20(1.2)^2

20(1.44) = $28.80

After 2 weeks the coupon is $28.80

D) To solve for the number of weeks (x) set the equation equal to $100:

100 = 20(1.2)^x

Divide both sides by 20:

5 = 1.2^x

Take the natural logarithm of both sides:

ln(5) = ln(1.2^x)

Use the logarithm rule to remove the exponent:

ln(5) = x ln(1.2)

Divide both sides by ln(1.2)

x = ln(5) / ln(1.2)

Divide:

X = 8.83

At 8.83 weeks the coupon would be $100, so after 9 weeks the coupon would be greater than $100

The answer is 9 weeks.

4 0

3 years ago

What’s the correct answer for this?

VMariaS [17]

Answer:

Second option is the correct answer

$(x+11)^2+(y+6)^2 = 324$

Step-by-step explanation:

$x^{2} +12y+22x+y^2-167=0\\x^{2}+22x +y^2 +12y-167=0\\(x^{2}+22x +121)-121 +(y^2 +12y+36)-36-167=0\\(x+11)^2+(y+6)^2-324 = 0\\\huge\red{\boxed{(x+11)^2+(y+6)^2 = 324}}\\$

5 0

3 years ago

Read 2 more answers

A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,

kenny6666 [7]

Answer:

(b) $\frac{1}{2}$

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

$\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}$

b. The mean of the sampling distribution

$\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}$

c. No; the proportion of males is $\frac{1}{4}$ while the mean is $\frac{1}{2}$ .

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0

3 years ago

Find the measure of.. (Image included) <br> I'll take all the help I can get please :)

sergey [27]

Answer:

$\sf\Huge\boxed{C.40}$

Step-by-step explanation:

Hello There!

Remember: sum of interior angles of a triangle = 180

so to find x we use this equation

180 = 90 + 7x + 5 + 9x + 5 ( the little square in the triangle indicates that the angle is a right angle. right angles have a measure of 90 so that's where the 90 came from.)

now we solve for x

step 1 combine like terms

90 + 5 + 5 = 100

7x + 9x = 16x

now we have 180 = 16x + 100

step 2 subtract 100 from each side

180 - 100 = 80

100 - 100 cancels out

now we have 80 = 16x

step 3 divide each side by 16

80/16 = 5

16x/16=x

we're left with x = 5

Finally we plug in 5 into x for angle a

7(5)+5

7*5=35

35+5=40

so we can conclude that the measure of angle A is 40 degrees

4 0

3 years ago

The coordinate grid shows points A through K. What point is a solution to the system of inequalities?

Eddi Din [679]

Answer:

Option D) F

Step-by-step explanation:

we have

$y < -2x+10$ -----> inequality A

The solution of the inequality A is the shaded area below the dashed line $y=-2x+10$

The y-intercept of the dashed line is (0,10)

The x-intercept of the dashed line is (5,0)

$y < \frac{1}{2}x-2$ ----> inequality B

The solution of the inequality B is the shaded area below the dashed line $y=\frac{1}{2}x-2$

The y-intercept of the dashed line is (0,-2)

The x-intercept of the dashed line is (4,0)

The solution of the system of inequalities is the shaded area between the two dashed lines

see that attached figure

Remember that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must lie on the shaded area of the solution

therefore

The solution are the points

E, F and G

8 0

3 years ago