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Elza [17]
3 years ago
7

Frequency of Deer at Local Pond

Chemistry
1 answer:
zavuch27 [327]3 years ago
4 0

Answer:

a

Explanation:

got it right in study island xD

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Question 2
Alenkinab [10]

Answer:

1.53 atm

Explanation:

From the question given above, the following data were obtained:

Volume = constant

Initial pressure (P₁) = stp = 1 atm

Initial temperature (T₁) = 273 K

Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K

Final pressure (P₂) =?

Since the volume is constant, the final pressure can be obtained as follow:

P₁ / T₁ = P₂ / T₂

1 / 273 = P₂ / 417

Cross multiply

273 × P₂ = 417

Divide both side by 273

P₂ = 417 / 273

P₂ = 1.53 atm

Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.

8 0
3 years ago
How does an atom become an atom of another element is
ivann1987 [24]
Can you give me the anwsers

3 0
3 years ago
16.6g CaCl2 dissolved in water and completely dissociates. The molality of chloride ions in 300g of water is
vova2212 [387]

Answer:

— The molality of chloride ions in 300g of water is. A) 1.00 molal. B) 0.500 molal. C) 0.0553 molal. D) 0.111 molal.

3 0
3 years ago
How many grams of iron contain 4.06X10^24 atoms of iron?
Oxana [17]
4.06x20^24/6.02x10^23 = 6.744 moles x 55.845 g/mole = 376.61868grams
4 0
3 years ago
How many moles of oxygen are consumed in the complete combustion of 1.60 moles of benzene, c6h6?
My name is Ann [436]

In the complete combustion of 1.60 moles of benzene, C6H6, 12 moles of oxygen, O2, is consumed.

Combustion is defined as the process of burning something. In chemistry, combustion refers to the chemical process between a fuel and an oxidant, usually oxygen to produce heat and light in the form of flame.

In a complete combustion, oxygen is sufficient to react with any hydrocarbons to produce carbon dioxide and water.

Balancing the combustion reaction of benzene, we have:

2C6H6 + 15 O2 = 12CO2 + 6H2O

Based on the balanced combustion reaction above, 2 moles of benzene requires 15 moles of oxygen to have a complete combustion.

If we have 1.60 moles C6H6,

moles O2 = mole ratio x mole of benzene

moles O2 = (15 moles O2/2 moles C6H6) x 1.60 moles C6H6

moles O2 = 12

To learn more about combustion: brainly.com/question/9913173

#SPJ4

3 0
2 years ago
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