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chubhunter [2.5K]
3 years ago
10

A mixture of krypton and argon gas is expanded from a volume of 88.0L to a volume of 100.0L, while the pressure is held constant

at 27.0atm. Calculate the work done on the gas mixture. Round your answer to 3 significant digits, and be sure it has the correct sign (positive or negative).
Chemistry
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

-3.28 × 10⁴ J

Explanation:

Step 1: Given data

  • Pressure exerted (P): 27.0 atm
  • Initial volume (Vi): 88.0 L
  • Final volume (Vf): 100.0 L

Step 2: Calculate the work (w) done by the gaseous mixture

We will use the following expression.

w = -P × ΔV = -P × (Vf - Vi)

w = -27.0 atm × (100.0 L - 88.0 L)

w = -324 atm.L

Step 3: Convert w to Joule (SI unit)

We will use the conversion factor 1 atm.L = 101.325 J.

-324 atm.L × 101.325 J/1 atm.L = -3.28 × 10⁴ J

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