Question

14th term of geometric sequence 7, 28, 112

Answer 1

Answer:

14th term of geometric sequence 7, 28, 112 is 469762048

Step-by-step explanation:

Geometric sequence : 7, 28, 112, .....

First term = a = 7

Common ratio = r =$\frac{a_2}{a_1}=\frac{a_3}{a_2}$

Common ratio = r =$\frac{28}{7}=\frac{112}{28}=4$

Formula of nth term =$a_n=ar^{n-1}$

Substitute n = 14

So,$a_{14}=7(4)^{14-1}$

$a_{14}=469762048$

Hence the 14th term of geometric sequence 7, 28, 112 is 469762048