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gogolik [260]
3 years ago
9

The tribute states of the ancient Aztec empire

Chemistry
2 answers:
Digiron [165]3 years ago
8 0

Answer:

made regular payments to the emperor.

Explanation:

The Aztec Empire was an alliance of three states: Mexico-Tenochtitlan, Texcoco, and Tlacopan. The area in and around the Valley of Mexico was ruled by these three city-states from 1428 to 1521. The state religion of the empire was polytheistic. The tribute states of the ancient Aztec empire made regular payments to the emperor.

nevsk [136]3 years ago
7 0

Answer:

B

Explanation:

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3 years ago
slader Consider the following reactions: A. uranium-238 emits an alpha particle; B. plutonium-239 emits an alpha parti- cle; C.
pishuonlain [190]

<u>Answer:</u>

<u>For A:</u> The equation is _{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> The equation is _{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> The equation is _{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

<u>Explanation:</u>

Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

Beta decay process is defined as the process the neutrons get converted into an electron and a proton. The released electron is known as the beta particle. In this process, the atomic number of the daughter nuclei gets increased by a factor of 1 but the mass number remains the same.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

<u>For A:</u> Uranium-238 emits an alpha particle

The nuclear equation for this process follows:

_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> Plutonium-239 emits an alpha particle

The nuclear equation for this process follows:

_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> Thorium-239 emits a beta particle

The nuclear equation for this process follows:

_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

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