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3 years ago

A line goes through points (1, 8) and (5, 6). What is the slope of the line?

Mathematics

2 answers:

kherson [118]3 years ago

7 0

-0.5

Step-by-step explanation:

$\frac{6 - 8}{5 - 1?} = - 0.5$

slope=

$\frac{y2 - y1}{x2 - x1}$

IrinaVladis [17]3 years ago

7 0

Answer:

-2/4

Explanation:

You label the first coordinate points as X(1) and Y(1) and the second coordinate points as X(2) and Y(2) and then apply the formula

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Two-thirds of the sum of a number squared and 5 is fourteen

RideAnS [48]

Answer:

2/3( x^2 + 5 ) = 14 or 2/3x^2 - 32/3

Step-by-step explanation:

Part 1:

Two-thirds ( 2/3 )

of the ( (---) )

sum ( + )

of a number squared ( x^2 ) and 5 ( + 5 )

is fourteen ( = 14 )

Part 2 (Not super confident about):

2/3( x^2 + 5 ) = 14

2/3x^2 + 10/3 = 14

2/3x^2 - 32/3

Hopefully this helps!

Brainliest please?

7 0

3 years ago

Question

meriva

Question:

In a neighbourhood pet show, each of the animals entered is equally likely to win. if there are 7 dogs, 6 cats, 3 birds, and 2 gerbils entered, what is the probability that a bird will win the top prize?

Answer:

Probability that a bird will win the top prize is 0.167

Step-by-step explanation:

Given:

The number of dogs = 7

The number of cats = 6

The number of birds = 3

The number of gerbils = 2

To Find:

Probability that a bird will win the top prize = ?

Solution:

Let us first find the total number of pets .

The Total number of pets = 7 + 6 + 3 + 2 = 18

Now the probability of a bird will win the top prize is

=> $\frac{\text {Number of birds}}{\text{ Total number of pets}}$

=> $\frac{3}{18}$

=> $\frac{1}{6}$

=>0.167

4 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

3 years ago

Solve this problem to find Y. 800 x Y = 4800

kupik [55]

Answer:

Step-by-step explanation:

800*Y=4800

Y=4800/800

Y=6

5 0

3 years ago

Read 2 more answers

An artist printed 1026 greeting cards and plans to package them for distribution. How many can be put into each box so theres no

OleMash [197]

Answer:

Step-by-step explanation:

18 is the only number given that can be divided without having a remainder or decimal.

1026 ÷ 18 = 57

4 0

3 years ago