Answer:
Let, X be the oxidation state of Cr in K
2
Cr
2
O
7
.
2(+1)+2X+7(−2)=0
2+2X−14=0
2X=12
X=+6
Hence, the oxidation state of Cr in K
2
Cr
2
O
7
is +6.
You need to give more explanation about it but if i understand a little abt what ur saying so i thinks it’s true