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KengaRu [80]
3 years ago
7

Which process works with erosion to break down rock?

Chemistry
2 answers:
Artyom0805 [142]3 years ago
7 0

Answer: weathering

Explanation:

I got it right on quiz

dalvyx [7]3 years ago
6 0

Answer:

weathering

Explanation:

one brakes it down the other carries it away

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The definition of chemical is “any substances that has a definite composition.” What does “definite composition” mean?
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Law of definite composition states that the elements in a given compound are always combined in the same proportion by mass. This law form the basis for the definition of a chemical compound.

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3 years ago
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What causes the change within every twenty four hours from day to night on Earth?
Marta_Voda [28]

Answer:

The Earth's rotation on its axis

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Imagine that you push on a large rock. At what point does your effort change the rock’s mechanical energy?
xz_007 [3.2K]
It changes when you have started pushing the rock because at that moment it has started moving
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4 years ago
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What volume in milliliters of 100 proof vodka (50% v/v ethanol) would be likely to kill a typical 360-g rat?
prohojiy [21]

The given question is incomplete, the complete question is:

The LD50 value for ethyl alcohol given orally to rats is 10.3 g/kg. What volume in milliliters of 100 proof vodka (50% v/v ethanol) would be likely to kill a typical 360-g rat?

Answer:

The correct answer is 9.4 ml.

Explanation:

Based on the given information, in rats the LD50 of ethyl alcohol is 10.3 g/kg.

As 1 Kg is 1000 grams

Now the value of LD50 of ethyl alcohol in rats is 10.3 grams/ 1000 grams

The volume of the lethal dose of vodka for a 360 gram rat would be,  

= 360 g × (10.3 g/1000 g)

= 3708 × 10⁻³ g

= 3.708 g

Now the volume of vodka can be determined by using the formula,  

V = mass/density

The density of ethanol is 0.789 g/ml

The volume would be,  

V = 3.708 g/0.789 g/ml

V = 4.70 ml

As 50 percent of Vodka is ethanol, the volume of vodka needed to kill a rat is,  

= 2 × Volume of ethanol

= 2 × 4.70 g/ml

= 9.4 ml

8 0
3 years ago
A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled.
vfiekz [6]
V1/T1 =V2/T2 (using charles law)

V1=6.00
V2=?
T1=273
T2=273

Making V2 the subject of formula the equation then becomes

V2= V1xT2/T1

6.00x263/273=6.0L
4 0
2 years ago
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