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zmey [24]
3 years ago
9

In the oscillating spring ball system, where is the velocity of the ball the greatest?

Physics
1 answer:
nlexa [21]3 years ago
6 0

The speed of an object in a mass-spring system is given under the function

v = \pm \sqrt{\frac{k}{m}(A^2-x^2)}

Here,

m = mass

k = Spring constant

A = Amplitude

x = Position

When the position is at the equilibrium point (x = 0), the speed will be maximum, and could even be expressed as

v_{max}= A\sqrt{\frac{x}{m}}

So the correct answer is B.

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A 5.00 kilogram block slides along a horizontal,frictionless surface at 10.0 meters per second. for 4.00 seconds. The magnitude
finlep [7]
In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
Mass of the block that is sliding = 5.00 kg
Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
                   = (5 * 10) Kg m/s
                   = 50 kg m/s
So the magnitude of the blocks momentum is 50 kg m/s. The correct option among all the given options is option "b".
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notka56 [123]
Two separate magnets.
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2)
earnstyle [38]

Answer:

0.0312J

Explanation:

Let x be the distance the staple moves:

x=0.150m-0.115m=0.035m

And spring constant is k=51.0N/m

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