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tangare [24]
3 years ago
5

You have a tree in your yard 4 ft to the left of and 5 ft in front of the corner of your porch. A circular fence 3 ft in radius

has its center at the tree. If the corner of your porch is the origin and forward is the positive y direction, what equation represents the circle formed by the fence in your yard?
Mathematics
1 answer:
Natalka [10]3 years ago
8 0

Answer:

(x+4)^2+(y-5)^2=9

Step-by-step explanation:

If the corner of your porch is the origin

  • 4 ft to the left, x=-4
  • 5 ft in front, y=5

The tree's location is at (-4,5).

  • A circular fence 3 ft in radius has its center at the tree(-4,5).

We want to determine the equation of a circle with center (-4,5) and radius 3 ft.

The equation of a circle center (h,k) with a radius of r is given as:

(x-h)^2+(y-k)^2=r^2

(h,k)=(-4,5), r=3

The equation formed by the fence therefore is:

(x-(-4))^2+(y-5)^2=3^2\\\\$Simplifying we obtain:\\\\(x+4)^2+(y-5)^2=9

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Step-by-step explanation:

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sdas [7]
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
\cfrac{2x}{x^2+2x-24}-\cfrac{x}{x^2-36}\quad 
\begin{cases}
x^2+2x-24\implies (x+6)(x-4)\\
--------------\\
x^2-36\implies x^2-6^2\\
(x-6)(x+6)
\end{cases}

\bf \cfrac{2x}{(x+6)(x-4)}-\cfrac{x}{(x-6)(x+6)}\impliedby 
\begin{array}{llll}
\textit{thus our LCD is}\\
(x-6)(x+6)(x-4)
\end{array}
\\\\\\
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\\\\\\
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