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ella [17]
3 years ago
12

There are currently 4 people signed up to play on a baseball team. The team must have at least 9 players.

Mathematics
1 answer:
stepan [7]3 years ago
5 0

Answer:

B

Step-by-step explanation:

B is correct because it includes 5 and everything higher than that. There needs to be at least 5 more people signing up, and this number line is the only one that shows that, since it includes 5 and more.

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I'm not sure how to do this, help?
Andrei [34K]
X*26=180 subtract 26 from 180 then you will find x.
 
7 0
3 years ago
The circular play area has a diameter of 16 ft. There is a walkway that surrounds the play area is 3' wide. What is the area of
Monica [59]

Answer: 179 sq. feet

Step-by-step explanation:

brainly.com/question/11852368#readmore

5 0
3 years ago
Ughh i suck at dilation
Ivenika [448]
Look at!!:
Pre image  A(3,4), B(1,5) C(6,6);
If you multiply these coordinates by 3/2, you get its images:

A(3,4)              ⇒ A`(3*3/2, 4*3/2)=(4.5, 6)
B(1,5)              ⇒B`(1.*3/2,  5*3/2)=(1.5, 7.5)
C(6,6)              ⇒C`(6*3/2, 6*3/2)=(9,9)

Therefore the scale factor is 3/2. 
When the scale factor of a dilation is >1, then we have an enlargement, an expansion.
In this case 3/2=1.5>1

Answer: 

The dilation is expansion.
The scale factor is 3/2. 
7 0
3 years ago
The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard
arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ 1^s^t statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

\frac{X-\mu}{\sigma} = Z

In this case we have:  \mu=5\ ft\sigma=0.4\ ft

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒2^n^d statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft  

Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒3^r^d statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒4^t^h statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0
3 years ago
Write any 4 laws of exponents.<br>​
emmainna [20.7K]

         \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

       <em>Write any 4 laws, or properties, of exponents.</em>

<em />

<em>        </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

\Large\text{Law number 1:-}

\Large\text{$a^n*a^m=a^{n+m}$}

\Large\text{It states that:-}

                        When we multiply together numbers with the same base,

                         we add the exponents.

\Large\text{Law number 2:-}

\Large\text{$a^m:a^n=a^{m-n}$}

\Large\text{It states that:-}

                     When we divide numbers with the same base, we

                     subtract the exponents.

\Large\text{Law number 3:-}

\Large\text{$(\displaystyle\frac{x}{y}) ^n=\frac{x^n}{y^n}$}

\Large\text{It states that:-}

                 If we have a fraction to a power, we raise the numerator and

               the denominator to that power.

And then last but not least,

\Large\textit{Law number 4:-}

\Large\text{$a^{-m} =\displaystyle\frac{1}{a^m}$}

\Large\text{It states that:-}

                   If we have a number with a negative exponent, we flip it over.

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}

6 0
2 years ago
Read 2 more answers
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