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artcher [175]
3 years ago
9

If I have the coordinates (4, 3) and (2, 2) what is distance do we get

Mathematics
2 answers:
Iteru [2.4K]3 years ago
6 0

Answer:

Step-by-step explanation:

gtnhenbr [62]3 years ago
6 0
By using the distance formula we apply the points

d=√((x_2-x_1)²+(y_2-y_1)²)

= root 5 or 2.236
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4) Solve for x: 4(2x - 10) = 12x + 10
Lera25 [3.4K]

Answer:

x=-25/2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve for y <br><br>2x - 5y = -12​
Andreyy89

Answer:

-4

Step-by-step explanation:

just add both of the sides then divide

5 0
3 years ago
Alex drove 135 miles in 3 hours at a constant speed
Dominik [7]
Speed = distance / time
speed = 135/3 = 45 miles per hr <==
7 0
3 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
HELP PLZ DUE RN BRAINIEST TO WHOEVER RIGHT
Jobisdone [24]

Answer:

x=1/3

hope this helps!!! :)

6 0
3 years ago
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