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Setler79 [48]
3 years ago
6

A parabola can be drawn given a focus of (1,3) and a directrix of x = -7. What

Mathematics
1 answer:
irakobra [83]3 years ago
8 0

Answer:

Below.

Step-by-step explanation:

The parabola will open to the right and will be symmetrical about y = 3.

The vertex is halfway between x = 1 and x = -7 making it at (-3, 3).

The p value is the distance between the vertex and the focus - here it is 1 - -3

= 4.

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Solve the inequality for y 2.9 < 5.6+y simplify your answer as much as possible
just olya [345]

Answer:

-2.7 < y

Step-by-step explanation:

2.9 < 5.6+y

Subtract 5.6 from each side

2.9-5.6 < 5.6-5.6+y

-2.7 < y

4 0
3 years ago
Please help!!!
Likurg_2 [28]

Answer: Hello! I believe your answer would be 162.

Step-by-step explanation: So the formula for Area on a rectangle is WxL. So length will be 9. But if you notice on the scale rectangle the width is the length times two. So the length on the real garden is 18.

6 0
3 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

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Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

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6 0
3 years ago
Find the x and y intercepts.
Roman55 [17]
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Add 9/2x to both sides

5y = 90 + 9/2x

Divide both sides by 5

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y = 9/10x + 18
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Gradient (m) = 9/10 or 0.9
and the y - intercept (c) = 18




3 0
3 years ago
Which of the following points is collinear with (1, 1), and (2, 2)? (4, 1) (3, 2) (5, 6) (3, 3)
aleksandrvk [35]
<span>Points (1, 1), and (2, 2) are on a line which has a slope of 1

ok?

The only point that lies on this line is (3,3).
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