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Lady_Fox [76]
3 years ago
12

Find the slope of the line through each pair of points (19,-2) (-11,10)

Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

\huge\boxed{-\frac{2}{5}}

Step-by-step explanation:

The slope of a line can be determined from two points via the slope formula. This is usually defined as the change in y divided by the change in x. It’s commonly represented using this formula:

  • \displaystyle \frac{\Delta y}{\Delta x}

Where \Delta represents “change in.”

The slope is basically just saying the rate of increase/decrease a function has when x increases by 1 - how much does y change when x increases by 1? We can find this by taking larger values and dividing by the rate at which we took the larger values. This derives the slope formula.

We can find the change in y and x in this function by analyzing the two points given. If we look at the change between each point, we can get the change since this is a line and thus has a constant slope.

  • The change in y will be 12. This is because from -2 to 10 is 10 units - 10 - (-2) = 12
  • The change in x will be -30. This is because from 19 to -11 is -30 units - -19 -11 = -30

Now that we have our change in x and y, we can substitute these values into the slope formula.

  • \displaystyle \frac{\Delta y}{\Delta x}
  • \displaystyle \frac{12}{-30}
  • \displaystyle -\frac{12}{30}
  • <em>Simplify - divide numerator and denominator by 6 </em>
  • <em />\displaystyle -\frac{2}{5}<em> </em>

<em />

Therefore, the slope of this line is -\frac{2}{5}.

Hope this helped!

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Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack
Rainbow [258]

Answer:

2

Step-by-step explanation:

Given the question :

Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?

Number of granolas = 6

Number of dried fruits = 10

Since the snackbag is to be designed in such a way that there should be no food leftover, the greatest number of snack bags Serena can make could be obtained by getting the highest common factor of (6 and 10)

____6____10

2___3____5

Here, the highest common factor of 6 and 10 is 2

Hence, the greatest number of snack bags she can make is 2.

5 0
3 years ago
Consider the function f(x) = 3x and the function g, which is shown below.
VLD [36.1K]

Answer:

<em>B. The graph of g is the graph of f shifted 2 units down</em>

Step-by-step explanation:

<u>Graph of Functions</u>

We have two functions:

f(x)=3^x

g(x)=3^x-2

Since g(x)=f(x)-2 it will be represented as an identical graph as that for f(x), but vertically displaced 2 units down. Let's check it by plugging some points

f(0)=3^0=1

g(0)=3^0-2=-1

f(1)=3^1=3

g(1)=3^1-2=1

f(3)=3^3=27

g(3)=3^3-2=25

We can notice the values of g(x) are always 2 units below f(x), thus the correct answer is

B. The graph of g is the graph of f shifted 2 units down

7 0
4 years ago
Let f(x) = x2 – 4, x &lt; 0. What is f-1?
Galina-37 [17]

Answer:

-3

Step-by-step explanation:

f(x) = x2 – 4

replace x with -1

f(-1) = (-1)^2 – 4

= -3

5 0
2 years ago
A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student
umka2103 [35]

Answer:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X_{M}= 69.8 represent the mean for the age of grandmother

\bar X_{F}= 71.6 represent the mean for the age of grandfather

s_{M}= 8.38 represent the sample deviation for the age of grandmother

s_{F}= 6.65 represent the sample deviation for the age of grandfather

n_M = n_F= 10

Solution to the problem

For this case the confidence interval is given by:

(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n_M +n_F-2=10+10-2=18

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that t_{\alpha/2}=2.101

And replacing we got:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

5 0
4 years ago
I need help answering this question
My name is Ann [436]

Answer:

55

Step-by-step explanation:

JL = JK + KL

84 = 3x+5  + 6x+7

Combine like terms

84 = 9x +12

Subtract 12 from each side

84-12 = 9x+12-12

72 = 9x

Divide by 9

72/9 = 9x/9

8 =x

We want KL

KL = 6x+7

   6*8 +7

    48+7

     55

4 0
3 years ago
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