Answer:
4.7 g
Explanation:
The reaction that takes place is:
- 3CaCl₂(aq) + 2Na₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6NaCl(aq)
First we <u>convert 4.8 g of CaCl₂ into moles</u>, using its <em>molar mass:</em>
- 4.8 g ÷ 110.98 g/mol = 0.0432 mol CaCl₂
Then we<u> convert CaCl₂ moles into Na₃PO₄ moles</u>, using the <em>stochiometric coefficients of the balanced reaction</em>:
- 0.0432 mol CaCl₂ *
= 0.0288 mol Na₃PO₄
Finally we <u>convert 0.0288 moles of Na₃PO₄ into grams</u>, using it<em>s molar mass</em>:
- 0.0288 mol Na₃PO₄ * 164 g/mol = 4.7 g
Answer:
Put the water out in the sun and the water will evaporate.
Explanation:
B) they have no charges and are inside an atom.*
Answer:
The correct answer is 4.58 grams.
Explanation:
Based on the Faraday's law of electrolysis, at the time of electrolysis, the amount of deposited substance is directly equivalent to the concentration of the flow of charge all through the solution. If current, I, is passed for time, t, seconds and w is the concentration of the substance deposited, then w is directly proportional to I*t or w = zIt (Here z refers to the electrochemical equivalent or the amount deposited when 1 C is passed).
For the reaction, n * 96500 C = molar mass
1C = molar mass/n*96500 = Equivalent wt / 96500
w = Equivalent wt / 96500 * I * t
In the given reaction,
Pb + PbO2 + 2HSO4- + 2H+ → 2PbSO4 + 2H2O, n = 2, the current or I drawn is 350 A, for time, t 12.2 seconds.
Now putting the values in the equation we get,
w = 207.19 / 2 * 96500 * 350 * 12.2 ( The molecular weight of Pb is 207.19 and the equivalent weight of Pb is 207.19 / 2)
w = 4.58 gm.
<u>Answer:</u> The correct option is C) 1.68 mol/L
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
Given values:
Given mass of 
= 150 g
Molar mass of = 180 g/mol
Volume of the solution = 0.50 L
Putting values in equation 1, we get:
Hence, the correct option is C) 1.68 mol/L
