Answer:
1.) 2.4
2.) 112 lbs
3.) 7.85 inches
4.) 6 lbs
5.) 2 lbs
6.) 67%
Explanation:
Given that
Radius of the wheel R = 1 foot
1 foot = 12 inches.
Radius of the axle r = 5 inches
1.) The mechanical advantage MA is :
MA = R/r = 12/5 = 2.4
2.) How much resistance force can ideally be overcome when an effort of 80 lbs is applied to the wheel of the water valve in problem 1?
MA = Load / effort
Where effort = 80 lbs
Substitute MA and effort into the formula
2.4 = Load / 80
Cross multiply
Load = 2.4 × 80 = 192 lbs
The resistance force to be overcome will be
Force = load - effort
Resistance force = 192 - 80 = 112 lbs
3) What is the linear distance traveled when a 2.5' diameter wheel makes one revolution
One revolution = 2π
Radius = 2.5 /2 = 1.25 inches
Linear distance S = angular distance Ø × radius r
S = Ør
S = 2π × 1.25
S = 7.85 inches
4. ) given that
Wheel radius R = 4
Axle radius r = 1
MA = 4/1 = 4
MA = Load / effort
4 = 24/ effort
Effort = 24/4 = 6 lbs
5.) 6 - 4 = 2lb
6.) Efficiency = MA / VR × 100
Efficiency = 4 / 6 × 100
Efficiency = 67%
