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aleksklad [387]
3 years ago
5

................................................................

Chemistry
2 answers:
solniwko [45]3 years ago
7 0

Answer:

..............,.,.,.,,..,,.,.,

crimeas [40]3 years ago
7 0
…………………………………………………..
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A ball was kicked by a player, the ball was stationary, then it gains a velocity of 5 m/s North. Did the ball accelerate or no?
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yes

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it started moving North 5 m/s

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A 519.93 gram sample of N2O is in a 7.05 L container. What is the pressure of the gas in atmospheres when the temperature is 125
Brut [27]

Answer:

17.27 atm

Explanation:

Use the ideal gas law or PV = nRT

We are solving for pressure here so lets isolate for P before we plug in values:

P = \frac{nRT}{V}

So first to get n or the number of moles we need to convert the grams of N2O to moles of N2O. We can do this by multiplying by the inverse of the molar mass like so:

\frac{519.93g(N2O)}{1} \frac{mol}{44.013g(N2O)}

Our grams of N2O would cancel and give us 11.813 mol of N2O

Now all thats left is to plug in and solve with the correct value for R which in this case for all of our units to cancel is 0.08206

P = \frac{(11.813)(0.08206)(125.63)}{7.05}

P = 17.27 atm

(I would double check the calculator work if it is for correctness just be sure)

4 0
3 years ago
Read 2 more answers
A student titrated a 1.0115 g sample of potassium hydrogen phthalate (hkc8h4o4 204.2285g/mol with sodium hydroxide. the initial
melomori [17]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
first determine the equation. KHP is a monoprotic acid, so it reacts with NaOH in a 1:1 ratio. 

<span>a) HKC8H4O4 + NaOH → NaKC8H4O4 + H2O </span>

<span>This allows you to calculate the molarity of NaOH, from the equation V1M1n2 = V2M2n1 </span>

<span>Molarity times volume will give you the number of moles of acid. You can work this out by dividing the mass used by the molar mass. For this question, you will have 1.0115/204.2285 moles KHP, so this value can be substituted for V1M1 in the equation. You need 38.46 mL of NaOH to titrate all the acid, so this will be V2. Now you find M2. </span>

<span>b) 1.0115/204.2285 × 1 = 38.46 × M2 × 1, so M2 = 0.0001288M </span>

<span>Now go on to part 3. Here, you use a similar calculation. The acid and base react in a 1:1 ratio, so n1 = n2 = 1. M2 = 0.1905 and V2 = 25.62. V1M1 will be calculated. </span>

<span>V1M1 × 1 = 25.62×0.0001288×1 = 0.003299856 </span>

<span>Now mass divided by molar mass = V1M1, so molar mass = mass/V1M1. </span>

<span>1.2587/0.003299856 = 381.44 g/mol</span>

4 0
3 years ago
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