4 years ago

Mass number is equal to

Chemistry

1 answer:

ValentinkaMS [17]4 years ago

4 0

The answer : protons and neutrons

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2 4.59 4.16 3.32*10^-4

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$Rate = k[A]^{x}[B]^{y}$

where k = rate constant

x and y are the orders wrt to A and B

To find x:

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To find y:

Divide rate of expt 3 by expt 1

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Therefore: x = 2, y = 0

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To find k

Use rate for expt 1:

$k = \frac{Rate1}{[A]^{2} } =\frac{1.82*10^{-4}M/s }{[3.40]^{2} } =1.57*10^{-5} s-1$

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3 years ago