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klasskru [66]
3 years ago
8

What is the wavelength of a wave having a frequency of 3.76 times 10 ^14 s^-1

Chemistry
1 answer:
yuradex [85]3 years ago
5 0

wavelength = 7.97 × 10⁻⁷ m

Explanation:

To calculate the wavelength of the wave we use the following formula:

wavelength = speed of light / frequency of oscillation

wavelength = 299792 × 10³ (m/s) / 3.76 × 10¹⁴ (s⁻¹)

wavelength = 79732 × 10⁻¹¹ m = 7.97 × 10⁻⁷ m

Learn more about:

 wavelength and frequency of a wave

brainly.com/question/2232652

brainly.com/question/2696232

#learnwithBrainly

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3 elements that have similar properties
qwelly [4]

Answer:The elements in the first column of the Periodic Table (other than hydrogen) are known as Group 1A metals, or alkali metals. When you compare the chemical properties of these elements (lithium, sodium, potassium, rubidium, cesium, and francium), what you'll notice is that they are all remarkably similar.

Explanation:

4 0
3 years ago
A student practicing for a track meet ran 300 meters in 30 seconds. what was her average speed?​
ololo11 [35]

Answer:

<h2>10 m/s</h2>

Explanation:

Her average speed can be found by using the formula

v =  \frac{d}{t}  \\

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t is the time taken

From the question we have

v =  \frac{300}{30}  = 10 \\

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<h3>10 m/s</h3>

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7 0
3 years ago
Rank these species by their ability to act as an oxidizing agent. cu+ mg2+ fe2+
natita [175]

Explanation:

The species or elements which gain electrons and reduces itself are known as oxidizing agent or oxidant.

Ability of an element to act as an oxidizing agent depends on its electrode potential.

The electrode potential of Cu^{+} is 0.52 V.

The electrode potential of Fe^2+ is -0.41 V.

The electrode potential of Mg^{2+} is -2.38 V.

Greater is the value of electrode potential, stronger will be the oxidizing agent.

Therefore, rank of these species by their ability to act as an oxidizing agent are as follows.

       Cu^{+} > Fe^2+ > Mg^{2+}

7 0
3 years ago
According to an informal 1992 survey, the drinking water in about one-third of the homes in Chicago had lead levels of about 10
wel

Answer:

10.2 mg

Explanation:

Step 1: Calculate the total amount of water she drank

1 year has 365 days and she lived in Chicago for 2 years = 2 × 365 days = 730 days.

If she drank 1.4 L of water per day, the total amount of water she drank is:

730 day × 1.4 L/day = 1022 L

Step 2: Calculate the amount of Pb in 1022 L of water

The concentration of Pb is 10 ppb (10 μg/L).

1022 L × 10 μg/L = 10220 μg

Step 3: Convert 10220 μg to milligrams

We will use the conversion factor 1 mg = 1000 μg.

10220 μg × 1 mg/1000 μg = 10.2 mg

8 0
3 years ago
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