Which is an advantage of conducting an experiment in a laboratory?

A 0.0434-m3 container is initially evacuated. Then, 4.19 g of water is placed in the container, and, after some time, all of the

adell [148]

Answer:

P =18760.5 Pa

Explanation:

Given that

Volume ,V= 0.0434 m³

Mass ,m= 4.19 g = 0.00419 kg

T= 417 K

If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation

Ideal gas equation P V = m R T

p=Pressure ,V = Volume ,m =mass

T=Temperature ,R=Universal gas constant

Now by putting the values

P V = m R T

For water R= 0.466 KJ/kgK

P x 0.0434 = 0.00419 x 0.466 x 417

P =18.7605 KPa

P =18760.5 Pa

Therefore the answer is 18760.5 Pa

6 0

4 years ago

If a gas has a gage pressure of 156 kPa, its absolute pressure is approximately

patriot [66]

The correct answer for the question that is being presented above is this one: "256 kpa." If a gas has a gage pressure of 156 kPa, its absolute pressure is approximately 256 kpa. Gauge pressure (GP) is 0 at atmospheric pressure (AP). Absolute pressure= GP + AP. Since atmospheric pressure is ca. 100 kpa; 100 + 156 is 256 kpa.

5 0

3 years ago

Read 2 more answers

Ii.

notka56 [123]

Answer:

toaster -- 15 A, 8 Ω
fry pan -- 10.83 A, 11.08 Ω
lamp -- 0.83 A, 144 Ω
fuse will blow

Explanation:

P = VI

I = P/V = P/120

R = V/I = V/(P/V) = V^2/P = 14400/P

Toaster: I = 1800/120 = 15 . . . amps

R = 14400/1800 = 8 . . . ohms

Fry pan: I = 1300/120 = 10.833 . . . amps

R = 14400/1300 = 11.08 . . . ohms

Lamp: I = 100/120 = 0.833 . . . amps

R = 14400/100 = 144 . . . ohms

The total current exceeds 20 A, so will blow the fuse.

5 0

4 years ago

A 29.0-kg block is initially at rest on a horizontal surface. A horizontal force of 71.0 N is required to set the block in motio

Julli [10]

Answer:

(a) $\mu_s=0.25$

(b) $\mu_k=0.20$

Explanation:

According to Newton's second law:

$\sum F_y:N=mg\\\sum F_x:F_a=F_f$

Recall that the frictional force is related jointly with the coefficient of friction and normal force $F_f=\mu N$ . Replacing in the above equation, we get the coefficient of friction: