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Whitepunk [10]
3 years ago
5

Question 6 (5 points)

Mathematics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

30 inches

Step-by-step explanation:

using a^2+b^2=c^2

72^2=5184

30^2=900

5184+900=6084

√6084=78

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How much interest is earned on $1470 at 4% for six months
Elenna [48]

Answer:

$29.4

Step-by-step explanation:

I assume the question is based on simple interest since you didn't specify

Using simple interest

Simple interest=P×R×T

Where,

P=principal=$1470

R=interest rate=4%=0.04

T=time=6 months=0.5 year

Simple interest=P×R×T

=1470×0.04×0.5

=29.4

Interest earned=$29.4

7 0
3 years ago
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USPshnik [31]
2.7777777 repeating decimal
5 0
3 years ago
Please help me !!!!!! I need help
kvv77 [185]

Answer:

  y +8 = -4(x -8)

Step-by-step explanation:

You recognize that the given equation is in slope-intercept form:

  y = mx + b

with m = 1/4 and b = 5.

A perpendicular line will have a slope that is the negative reciprocal of this value of m, so the desired slope is ...

  -1/m = -1/(1/4) = -4

The point-slope form of the equation for a line is ...

  y -k = m(x -h) . . . . . for slope m through point (h, k)

Using m=-4 and (h, k) = (8, -8), the point-slope form of the equation for the line you want is ...

  y +8 = -4(x -8)

3 0
3 years ago
What is the product?<br><br> One-eighth times three-elevenths
Nastasia [14]

Answer:

3/88

Step-by-step explanation:

when multiplying fractions, you can just multiply across. make sure to simplify!

7 0
3 years ago
The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation
mafiozo [28]

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = \mu = 69

Standard deviation = \sigma = 7

Formula : z=\frac{x-\mu}{\sigma}

Now At x = 55

z=\frac{55-69}{7}

z=-2

At x = 76

z=\frac{76-69}{7}

z=1

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = 0.8185 \times 100 = 81.85\%

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

7 0
3 years ago
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