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3 years ago

If a car with a mass of 5Kg, has a momentum of 25kgm/s, how fast is it travelling?

Physics

2 answers:

Fantom [35]3 years ago

8 0

Answer:

5m/s

Explanation:

p=mv, or momentum (p) is equal to mass (m) times velocity (v).

so:

m=5Kg

p=25Kgm/s

v=p÷m

v=25÷5

v=5m/s

hoped this helped :)

Anna35 [415]3 years ago

6 0

Answer:

5hrs

Explanation:

Mass•Accelleration=Momentum (5kg•5hrs=25Mps)

Mass÷Momentum=Accelleration (25Mps÷5kg=5hrs)

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xeze [42]

Answer:

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Given that,

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3 years ago

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Black_prince [1.1K]

The initial momentum of the system can be expressed as,

$p_i=m_1u_1+m_{2_{}}u_2$

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Plug in the known expressions,

$\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ m_2v_2=m_1u_1+m_2u_2-m_1v_1 \\ v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2} \end{gathered}$

Initially, the second mass move towards the first mass therefore the initial speed of second mass will be taken as negative and the recoil velocity of first mass is also taken as negative.

Plug in the known values,

$\begin{gathered} v_2=\frac{(1.16\text{ kg)(8.64 m/s)+(1.98 kg)(-3.34 m/s)-(1.16 kg)(-2.16 m/s)}}{1.98\text{ kg}} \\ =\frac{10.02\text{ kgm/s-}6.61\text{ kgm/s+}2.51\text{ kgm/s}}{1.98\text{ kg}} \\ =\frac{5.92\text{ kgm/s}}{1.98\text{ kg}} \\ \approx2.99\text{ m/s} \end{gathered}$

Thus, the final velocity of second mass is 2.99 m/s.

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1 year ago

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