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2 years ago

If a car with a mass of 5Kg, has a momentum of 25kgm/s, how fast is it travelling?

Physics

2 answers:

Fantom [35]2 years ago

8 0

Answer:

5m/s

Explanation:

p=mv, or momentum (p) is equal to mass (m) times velocity (v).

so:

m=5Kg

p=25Kgm/s

v=p÷m

v=25÷5

v=5m/s

hoped this helped :)

Anna35 [415]2 years ago

6 0

Answer:

5hrs

Explanation:

Mass•Accelleration=Momentum (5kg•5hrs=25Mps)

Mass÷Momentum=Accelleration (25Mps÷5kg=5hrs)

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Answer:

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$r = \sqrt{50 - 40.71} = \sqrt{9.29}$

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2 years ago

A car traveling with an initial velocity of 12 m/s accelerates at a constant rate of 2.2 m/s2 for a time of 4 seconds.

bazaltina [42]

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3 years ago

1. An asphalt block has a mass of 90 kg and a volume of 0.075 m. Determines the density of the asphalt.

Kisachek [45]

Answer:

1. Density = 1200[kg/m^3]; 2. Volume= 0.005775[m^3], mass= 15.59[kg]

Explanation:

1. We know that the density is defined by the following expression.

$Density = \frac{mass}{volume} \\where:\\mass=90[kg]\\volume=0.075[m^{3} ]\\density=\frac{90}{0.075} \\density=1200[\frac{kg}{m^{3} }]$

2. First we need to convert the units to meters.

wide = 35[cm] = 35/100 = 0.35[m]

long = 11 [dm] = 11 decimeters = 11/10 = 1.1[m]

Thick = 15[mm] = 15/1000 = 0.015[m]

Now we can find the density using the expression for the density.

$density= \frac{mass}{volume} \\where:\\volume = wide*long*thick\\volume=0.35*1.1*0.015 = 0.005775[m^3]\\\\mass= density*volume = 2700*0.005775 = 15.59[kg]$

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3 years ago

Multiple-Concept Example 6 reveiws the principles that play a role in this problem. A nuclear power reactor generates 2.3 x 109

r-ruslan [8.4K]

Answer:

change in mass = 2.41*10^{8}kg

Explanation:

The change in the mass can be computed by using the relation

$E=\Delta mc^2\\\Delta m=\frac{E}{c^2}$ (1)

That is, the energy liberated comes from the mass of the nuclear fuel. The energy generated in one year is

$E=Pt=2.3*10^{9}\frac{J}{s}*1 year*\frac{365.25 day}{1 year}*\frac{24h}{1 day}*\frac{3600s}{1h}=7.25*10^{16}J$

Hence, by replacing in the equation (1) you have (c=3*10^{8}m/s)

$\Delta m=\frac{7.25*10^{16}J}{3*10^{8}\frac{m}{s}}=2.41*10^{8}kg$

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