The velocity when function p(t)=11 is 8 .
According to the question
The position of a car at time t represented by function :
Now,
When function p(t) = 11 , t will be
11 = t²+2t-4
0 = t² + 2t - 15
or
t² +2t-15 = 0
t² +(5-3)t-15 = 0
t² +5t-3t-15 = 0
t(t+5)-3(t+5) = 0
(t-3)(t+5) = 0
t = 3 , -5
as t cannot be -ve as given ( t≥0)
so,
t = 3
Now,
the velocity when p(t)=11
As we know velocity = 
therefore to get the value of velocity from function p(t)
we have to differentiate the function with respect to time
v(t) = 2t + 2
where v(t) = velocity at that time
as t = 3 for p(t)=11
so ,
v(t) = 2t + 2
v(t) = 2*3 + 2
v(t) = 8
Hence, the velocity when function p(t)=11 is 8 .
To know more about function here:
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If the transformer’s primary coil has 20 times as many turns of wire in it as the secondary coil has, then the secondary coil provides a small voltage rise for the large amount of current that flows through it.
Answer: Option B
<u>Explanation:</u>
A transformer has a two types of coils, the first one is primary coils and the second one is secondary coil. A secondary coils with hardly any turns in it provides the charges going through it just limited quantities of energy.
Without a long separation over which to do chip away at the charges streaming in the loop, the transformer delivers just a little ascent in the voltage of those charges. Be that as it may, the coil can give this little voltage to ascend to a huge current without requiring an excess of power supply from the input circuit.
Answer:
D. 24 hours, 365 days
Explanation:
please mark me brainlist
and this is correct answer
Answer:
0.369 V
<u>Explanation:</u>
Given :
Capacitance ( c ) = 650 × 10–4 F
Charge ( q ) = 24 × 10–3 C
We are asked to find potential difference ( v )!
We know:
q = c v
= > v = q / c
Putting values here we get:
= > v = ( 24 × 10–3 ) / ( 650 × 10–4 ) V
= > v = 240 / 650 V
= > v = 24 / 65 V
= > v = 0.369 V
Therefore, potential difference between the plates is 0.369 V
I think the answer is 3, population.
