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3 years ago

What is the momentum of a 100-kilogram fullback carrying a football on a play at a velocity of 3.5. m/sec

Physics

2 answers:

podryga [215]3 years ago

7 0

Answer: 350 kg m/s

Explanation: Momentum can be defined as "mass in motion."

P=MV

P = momentum

M=mass

V=velocity

In the question, we were given;

M= 100-kilogram

V= 3.5. m/sec

Therefore,

Momentum= Mass * velocity

Momentum= 100kg * 3.5 m/sec

Momentum= 350kg.m/sec.

Olenka [21]3 years ago

6 0

Answer:

350 kg m/s

Explanation:

Momentum = mass × velocity

p = mv

p = (100 kg) (3.5 m/s)

p = 350 kg m/s

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Two Charged spheres of 6.4 nC charge are 16 cm apart. What is the magnitude of the field in middle? ( n = 10^-9, 100 cm = 1 m)

emmainna [20.7K]

Answer:

zero

Explanation:

q = 6.4 nC = 6.4 x 1 0^-9 C

d = 16 cm = 0.16 m

r = 16 / 2 = 8 cm = 0.08 m

Electric field at P due to the charge placed at A

Ea = k q / r^2

Ea = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards right

Ea = 9000 Towards right

Electric field at P due to the charge placed at B

Eb = k q / r^2

Eb = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards left

Eb = 9000 Towards left

The magnitude of electric field is same but teh direction is opposite, so the resultant electric field at P is zero.

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3 years ago

What is the significance of the direction of an electric field line at some point on the line?

Lemur [1.5K]

Answer with Explanation:

The direction of the electric field line at any point gives us the direction of the electric force that will act on a positive charge if placed at the point. We know that if we place a charge in an electric field it will experience a force, as we know that force is a vector quantity hence it requires both magnitude and direction for it's complete description. The direction of this electric force that acts on a charge is given by the direction of the electric field in the space. In case the charge is negatively charged electric force will act on it in the direction opposite to the direction of electric field at the point.

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4 years ago

An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N

algol13

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

ma = Eq

a = Eq/m

where,

E = electric field intensity = 120 N/C

q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

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3 years ago

a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel d

trasher [3.6K]

50π m ≈ 157 m
Explanation:
100 rev/min (2π rad/rev) / (60 sec/min) = 3⅓π rad/s
d = ωrt = 3⅓π(0.50)(30) = 50π m ≈ 157 m

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3 years ago

Define oxidation number

Delicious77 [7]

<span>a number assigned to an element in a chemical combo that represents the number of electrons lost or gained by atom of the element in the compound.</span>

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3 years ago