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Alisiya [41]
2 years ago
11

What is the momentum of a 100-kilogram fullback carrying a football on a play at a velocity of 3.5. m/sec

Physics
2 answers:
podryga [215]2 years ago
7 0

Answer: 350 kg m/s

Explanation: Momentum can be defined as "mass in motion."

P=MV

P = momentum

M=mass

V=velocity

In the question, we were given;

M= 100-kilogram

V= 3.5. m/sec

Therefore,

Momentum= Mass * velocity

Momentum= 100kg * 3.5 m/sec

Momentum= 350kg.m/sec.

Olenka [21]2 years ago
6 0

Answer:

350 kg m/s

Explanation:

Momentum = mass × velocity

p = mv

p = (100 kg) (3.5 m/s)

p = 350 kg m/s

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Help, please
Mice21 [21]

Answer:

A and A

Explanation:

see paper for work! :)

8 0
2 years ago
Come si esprime il numero 0,00123 in notazione scientifica?
Inessa [10]

Answer:

0,00123 = 1,2*10^{-3}

Explanation:

To write down correctly the number 0,00123 in scientific notation, you take into account that the scientific notation demands that there in only one number after the comma ( , ). Furthermore, it is necessary that you move the comma to the right of the first number different of zero, in this case the number 1. To do this you move the comma three positions.

Then, you have to multiply the expresion 1.23 by 10 with an exponential -3 (because of the movement of the comma in three positions). That is:

0,00123 = 1,23*10^{-3}

But it is mandatory that nly one number can stay after the comma, so, you approximate the number three. In this case, the number is lower than 5, hence, you approximate 3 to 0.

Finally, you have:

0,00123 = 1,2*10^{-3}

3 0
3 years ago
9. A radioisotope has a half-life of 4.50 min and an initial decay rate of 8400 Bq. What will be
Akimi4 [234]

Answer:

525 Bq

Explanation:

The decay rate is directly proportional to the amount of radioisotope, so we can use the half-life equation:

A = A₀ (½)^(t / T)

A is the final amount

A₀ is the initial amount,

t is the time,

T is the half life

A = (8400 Bq) (½)^(18.0 min / 4.50 min)

A = (8400 Bq) (½)^4

A = (8400 Bq) (1/16)

A = 525 Bq

8 0
3 years ago
For general projectile motion, the horizontal component of a projectile's velocity aSelect one:O a. continuously increases.O b.
liubo4ka [24]

ANSWER:

d. remains a non-zero constant.

STEP-BY-STEP EXPLANATION:

If we consider that there is no air resistance and that the horizontal component would be at x, the velocity remains a non-zero constant

3 0
1 year ago
Can someone answer this 2 correctly please
ahrayia [7]

Answer:

I know the first one is C.) 4J. I don't know of the answer for the second oneis suppose to be in N/m form? but I got

2,500N/m

5 0
3 years ago
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