What is the momentum of a 100-kilogram fullback carrying a football on a play at a velocity of 3.5. m/sec

Physics

2 answers:

podryga [215]3 years ago

7 0

Answer: 350 kg m/s

Explanation: Momentum can be defined as "mass in motion."

P=MV

P = momentum

M=mass

V=velocity

In the question, we were given;

M= 100-kilogram

V= 3.5. m/sec

Therefore,

Momentum= Mass * velocity

Momentum= 100kg * 3.5 m/sec

Momentum= 350kg.m/sec.

Olenka [21]3 years ago

6 0

Answer:

350 kg m/s

Explanation:

Momentum = mass × velocity

p = mv

p = (100 kg) (3.5 m/s)

p = 350 kg m/s

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The angular momentum of a flywheel having a rotational inertia of 0.142 kg·m2 about its central axis decreases from 7.20 to 0.14

luda_lava [24]

Answer:

3.3619 Nm

54.27472 rad

182.46618 J

86.88 W

Explanation:

$L_i$ = Initial angular momentum = 7.2 kgm²/s

$L_f$ = Final angular momentum = 0.14 kgm²/s

I = Moment of inertia = 0.142 kgm²

t = Time taken

Average torque is given by

$\tau_{av}=\frac{L_f-L_i}{\Delta t}\\\Rightarrow \tau_{av}=\frac{0.14-7.2}{2.1}\\\Rightarrow \tau_{av}=-3.3619\ Nm$

Magnitude of the average torque acting on the flywheel is 3.3619 Nm

Angular speed is given by

$\omega_i=\frac{L_i}{I}$

Angular acceleration is given by

$\alpha=\frac{\tau}{I}$

From the equation of rotational motion

$\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=\frac{L_i}{I}\times t+\frac{1}{2}\times \frac{\tau}{I}\times t^2\\\Rightarrow \theta=\frac{7.2}{0.142}\times 2.1+\frac{1}{2}\times \frac{-3.3619}{0.142}\times 2.1^2\\\Rightarrow \theta=54.27472\ rad$