<span>54.8 g of MgI2 can be produced.
To solve this, you need to determine the molar mass of each reactant and the product. First, look up the atomic weights of iodine and magnesium
Atomic weight of Iodine = 126.90447
Atomic weight of Magnesium = 24.305
Molar mass of MgI2 = 24.305 + 2 * 126.90447 = 278.11394
Now determine how many moles of Iodine and Magnesium you have
moles of Iodine = 50.0 g / 126.90447 g/mol = 0.393997154 mole
moles of Magnesium = 5.15 / 24.305 g/mol = 0.211890557 mole
Since for every magnesium atom, you need 2 iodine atoms and since the number of moles of available iodine isn't at least 2 times the available moles of magnesium, iodine is the limiting reagent.
So figure out how many moles of magnesium will be consumed by the iodine
0.393997154 mole / 2 = 0.196998577 mole.
This means that you can make 0.196998577 moles of MgI2. Now simply multiply by the previously calculated molar mass of MgI2
0.196998577 mole * 278.11394 g/mole = 54.78805 g
Round the result to the correct number of significant figures.
54.78805 g = 54.8 g</span>
I would put, A substance has two different parts of it, a pure substance and a compound and mixtures have two as well called, homogenous mixtures and hetrogeneous mixtures.
Tigers and lions able to mate to produce cubs,but those cubs would not be able to go on to produce any off spring because their sex chromosomes do not match.
Explanation:
Tigers and lions mate to produce ligers and tilons but they do not produce viable sperms or egg.
In an organism there are two copies of chromosomes present in the somatic cells.
But in case of sex cells they receive each set from mother and father. which they duplicate and divide during formation of gametes via meiosis.
in such case if the sets are recieved from two different species then after pairing a mismatch will occur in the gene loci.For example, a eye colour gene may correspond to a paw length gene.
Thus the gametes when produced will not be viable.
