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nikklg [1K]
3 years ago
6

The following three equations represent reactions done in this lab exercise. Classify each reaction by their type. Note there ma

y be more than one way to classify a reaction
1. Cu(s)+4HNO3(aq)⟶Cu(NO3)2(aq)+2NO2(g)+2H2O(l)
a. precipitation.
b. double displacement.
c. decomposition.
d. single displacement.
e. oxidation / reduction.
f. synthesis / combination.
2. Cu(NO3)2(aq)+2NaOH(aq)⟶Cu(OH)2(s)+2NaNO3(aq)
a. synthesis / combination.
b. single displacement.
c. oxidation / reduction.
d. decomposition.
e. double displacement.
f. precipitation.
3. CuO(s)+2HCl(aq)⟶CuCl2(aq)+H2O(l)
a. precipitation.
b. double displacement.
c. synthesis / combination.
d. oxidation / reduction.
e. single displacement.
f. decomposition.
Chemistry
1 answer:
gulaghasi [49]3 years ago
6 0

Answer: 1. Cu(s)+4HNO_3(aq)rightarrow Cu(NO_3)_2(aq)+2NO_2(g)+2H_2O(l) : oxidation reduction

2. Cu(NO_3)_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaNO_3(aq) : precipitation

3. CuO(s)+2HCl(aq)\rightarrow CuCl_2(aq)+H_2O(l) : Double displacement

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Cu(s)+4HNO_3(aq)rightarrow Cu(NO_3)_2(aq)+2NO_2(g)+2H_2O(l)

Double displacement reaction is defined as the reaction where exchange of ions takes place. Double displacement reaction in which one of the product remain in solid form are represented by (s) after their chemical formulas. Such double displacement reaction are called as precipitation reaction.

Cu(NO_3)_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaNO_3(aq)

Double displacement reaction is defined as the reaction where exchange of ions takes place.

CuO(s)+2HCl(aq)\rightarrow CuCl_2(aq)+H_2O(l)

Single displacement reaction is defined as the reaction where more reactive element displaces a less reactive element from its chemical reaction.

Decomposition reaction is defined as the reaction where a single substance breaks down into two or more simpler substances.

Synthesis/Combination reaction is defined as the reaction where substances combine in their elemental state to form a single compound.

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Answer:

True.

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If the volume of the original sample in Part A ( P1 = 242 torr , V1 = 27.0 L ) changes to 80.0 L , without a change in the tempe
Brrunno [24]

The new pressure is 81.675 torr

Since temperature and moles are held constant, we use Boyle's Law:

A gas law known as Boyle's law asserts that a gas's pressure is inversely proportional to its volume when it is held at a fixed temperature and of a given mass.

To put it another way, as long as the temperature and volume of the gas remain constant, the pressure and volume of the gas are inversely proportional to one another.

The Anglo-Irish chemist Robert Boyle proposed Boyle's law in the year 1662.

P1V1=P2V2. Simply plug in your values. The units can remain in torr. Converting to atmospheres is not needed.

(242 torr)(27.0 L)=P2(80.0 L)

P2=[(242)(27)]/80 = 81.675 torr

Hence The new pressure is 81.675 torr

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5 0
2 years ago
What volume would 0.735 moles of O2 gas occupy at STP
tatiyna

Answer:

16.5 dm³

Explanation:

Data Given:

no. moles of O₂ =  0.735 moles

volume of O₂ = ?

Solution:

Now

we have to find volume of O₂ gas

Formula used for this purpose

                   No. of moles = Volume / molar volume

where

molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol

              No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)

Put values in equation 1

                0.735 = Volume of O₂ / 22.4 dm³/ mol

rearrange above equation

              Volume of O₂ = 0.735 x 22.4 dm³/ mol

              Volume of O₂ = 16.5 dm³

So,

the volume of O₂ at STP is 16.5 dm³

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