What has an atomic number of 1

Mario places 10 mL of water in a test tube and heats the liquid over a Bunsen burner for 2 minutes. After removing the test tube

monitta

Mario places 10 mL of water in a test tube and heats the liquid over a Bunsen burner for 2 minutes. After removing the test tube from the Bunsen burner, there are 6 mL of water left in the test tube. This experiment is a good example of a physical change involving phase changes.

6 0

3 years ago

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Enter the balanced complete ionic equation for HCl(aq)+K2CO3(aq)→H2O(l)+CO2(g)+KCl(aq). Express your answer as a chemical equati

Marat540 [252]

Answer: The net ionic equation is given below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

These ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of hydrochloric acid and potassium carbonate is given as:

$2HCl(aq.)+K_2CO_3(aq.)\rightarrow H_2O(l)+CO_2(g)+2KCl(aq.)$

Ionic form of the above equation follows:

$2H^+(aq.)+2Cl^-(aq.)+2K^+(aq.)+CO_3^{2-}(aq.)\rightarrow CO_2(g)+H_2O(l)+2K^+(aq.)+2Cl^-(aq.)$

As, potassium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

$2H^+(aq.)+CO_3^{2-}(aq.)\rightarrow CO_2(g)+H_2O(l)$

Hence, the net ionic equation is given above.

7 0

3 years ago

Complete the chemical equation related to the formation of sodium chloride

son4ous [18]

Answer:

sodium + chlorine --> sodium chloride

3 0

3 years ago

What is the correct way to write 0.0000250 m in scientific notation?

yulyashka [42]

Scientific notation is: n * 10^a, where n is a number between 1 and 10 ( but not 10 itself ) and a is an integer.
We move decimal place to the left to create a new number from 1 to 10.
Answer:
0.0000250 m = 2.5 * 10^(-5) m.

7 0

3 years ago

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52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)

Elan Coil [88]

Answer:

0.0585 M

Explanation:

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)

First we calculate the inital number of moles of each reagent, using the given volumes and concentrations:

0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂

0.415 M NaCl * 38.5 mL = 16.0 mmol NaCl

Then we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the stoichiometric coefficients of the reaction:

16.0 mmol NaCl * $\frac{1mmolPb(NO_3)_2}{2mmolNaCl}$ = 8.00 mmol Pb(NO₃)₂

Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:

13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂

Finally we divide the number of moles by the final volume to calculate the concentration:

5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 M

6 0

3 years ago