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horsena [70]
2 years ago
8

Based on Archimedes' principle, we know that if an object displaces a given weight of water, then the object is being buoyed up

by an equal amount of force.
true or false?
Physics
2 answers:
Virty [35]2 years ago
8 0
True. If the amount displaced is more than the mass, it floats. If the amount is less than the mass, it will sink.
user100 [1]2 years ago
7 0

Answer:

The answer is True.

Explanation:

According to the Archimedes' principle, the buoyant force is equal to the submerged volume multiplied by the density of the displaced liquid; This happens because when the body is submerged, the fluid will exert an equal and opposite direction force, due to the change in pressure.

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HELP ITS DUE IN 4 MINUTES
DochEvi [55]

Answer:

The nephew

Explanation:

The nephew has a seeing eye dog which means the nephews tracks are the dogs tracks, and the dog tracks are not covered by anything which means the dog was last and stole the butterfly.

<u><em>Hope this helps!</em></u>

6 0
3 years ago
A 6.9-kg wheel with geometric radius m has radius of gyration computed about its mass center given by m. A massless bar at angle
Vilka [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is  \alpha =2.538 \  rad/s^2

Explanation:

From the question we are told that

  The mass of the wheel is  m =  6.9  kg

   The radius is  r =  0.69 \  m

    The radius of gyration is  k_G = 0.4\  m

    The angle is  \theta = 47^o

    The force which the massless bar is subjected to F = 22.5 \  N

Generally given that the wheels rolls without slipping on the flat stationary ground surface, it implies that  point A is the  center of rotation.

  Generally the moment of  inertia about A is mathematically represented as

     I_a =  I_G + M* r^2

Here I_G is the moment of inertia about G with respect to the radius of gyration  which is mathematically represented as

    I_G =  M *  k_G

=>I_a = k_G*  M + M* r^2

=>I_a =0.4 * 6.9  + 6.9 * 0.69^2

=>I_a =6.045 \  kg \cdot m^2

Generally the torque experienced by the wheel  is mathematically represented as

       \tau =  F *  cos (47)

=>     \tau =  22.5 *  cos (47)

=>     \tau =  15.34 \ kg \cdot m^2 \cdot s^{-2}

Generally this torque is also mathematically represented as

     \tau = I_a * \alpha

=>   15.34  =  6.045 * \alpha

=>   \alpha =2.538 \  rad/s^2

4 0
3 years ago
If a dog is accelerating at a constant rate of 6.57 m/s2, what is the mass of the dog if 25 N of force is being applied to it?
Oliga [24]

Answer:

<h3>The answer is 3.81 kg</h3>

Explanation:

The mass of the dog can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{25}{6.57}  \\  = 3.80517503

We have the final answer as

<h3>3.81 kg</h3>

Hope this helps you

8 0
2 years ago
The Law of Conservation of Mass states that mass can be destroyed during a chemical change.
Vesna [10]
The law of conservation of mass states that mass can be destroyed during a chemical change is TRUE
5 0
2 years ago
What is released when rocks shift or move along a tectonic plate boundary?
Phoenix [80]

Answer:

juuhu

Explanation:

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2 years ago
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