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babunello [35]
3 years ago
13

En un recipiente cerrado a 25°C disponemos de un gas sometido a una presión de 250.000 Pa. Luego, sin que cambie el volumen, con

seguimos una presión de 350.000 Pa. ¿a qué temperatura habremos tenido que calentar el gas?.
Chemistry
1 answer:
SSSSS [86.1K]3 years ago
3 0

Answer:

El gas se calentó a 35°C

Explanation:

Para resolver este problema es necesario aplicar la Ley de Gay Lussac donde en una situación en la que un gas no modifica su volumen, su temperatura será directamente proporcional a la presión.

Podemos pensar que se describe desde la Ley de Gases Ideales donde:

P . V = n . R . T

para la situacion 1

y P . V = n . R . T para la situacion 2

Como V, n y R son constantes:

P₁ / T₁ = P₂ / T₂

250000 Pa / 25°C = 350000 Pa / T₂

T₂ = 350000 Pa . 25°C / 250000 Pa → 35°C

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