All categories

3 years ago

PLEASE HELP!

Chemistry

1 answer:

Scilla [17]3 years ago

8 0

Answer:

P₂ = 450 kiloPascals

Explanation:

Boyle's law :))

P₁V₁ = P₂V₂

300*75 = P₂*50

P₂*50= 300*75

P₂ = 300*75/50 = 450

P₂ = 450 kiloPascals

The weight has expanded because of pressure of gas.

You might be interested in

Consider the reaction, 2 D(g) + 3 E(g) + F(g) => 2 G(g) + H(g) When H is increasing at 0.54 mol/Ls, how quickly is F decreasi

Serga [27]

Jkiillmcxujbj u ioik.

5 0

3 years ago

A water treatment plant receives the source water with an average Ca2+ concentration of 46.9 mg/L and Mg2+ concentration of 14.8

Veronika [31]

Answer:

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

Explanation:

Concentration of calcium ions = 46.9 mg/L

Concentration of magnesium ions = 14.8 mg/L

Volume of solution treated everyday , V= 80 million gal

= $80\times 10^6 gal=4.546\times 80\time 10^6 L=3.637\times 10^8 L$

1 gallon = 4.546 Liter

Mass of calcium ion in V = $46.9 mg/L\times 3.637\times 10^8 L$

= $1.706\times 10^{10} mg$

1 mg = 0.001 g

$1.706\times 10^{7} g$

Moles of calcium ions = $\frac{1.706\times 10^{7} g}{40 g/mol}=426,500 mol$

From 1 mole of calcium ion 1mol of carbonate is formed . then from 426,500 moles of calcium ion will form :

$\frac{1}{1}\times 426,500 mol=426,500 mol$ of calcium carbonate

Mass of 426,500 moles of calcium carbonate:

426,500 mol × 100 g/mol = 42,650,000 g = 42,650 kg

Mass of magnesium ion in V = $14.8 mg/L\times 3.637\times 10^8 L$

= $5.382\times 10^{9} mg$

= $5.382\times 10^{6} g$

Moles of magnesium ions = $\frac{5.382\times 10^{6} g}{24 g/mol}=224,250 mol$

From 1 mole of magnesium ion 1 mol of magnesium hydroxide is formed . then from 224,250 moles of magnesium ion will form :

$\frac{1}{1}\times 224,250 mol=224,250 mol$ of magnesium hydroxide

Mass of 224,250 moles of magnesium hydroxide:

224,250 mol × 58 g/mol = 13,006,500 g = 13,006.5 kg

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

3 0

3 years ago

Heat of fusion (?Hfus) is used for calculations involving a phase change between solid and liquid, with no temperature change. F

Butoxors [25]

Answer:

q = 38,5 kJ

Explanation:

In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:

q = C×m×ΔT

Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)

Replacing:

q = 4,184J/g°C×92,0g×100°C

q = 38493 J, in kilojoules:

q = 38,5 kJ

I hope it helps!

6 0

3 years ago

What is the electron configuration for Sodium (Na)?

SpyIntel [72]

The electron configuration for Sodium (Na) is [Ne] 3s1

8 0

3 years ago

Read 2 more answers

Interpret, in terms of atoms and in terms of moles, the supscript in a chemical formula C2H6

tigry1 [53]

Carbon (24.00)(2)+hydrogen(1.01)(6)

3 0

3 years ago