All categories

3 years ago

How many moles are present in 360 grams of water.

Chemistry

1 answer:

alexandr402 [8]3 years ago

4 0

Answer:

From point, 1 mole of water = molar mass of water =18g 20 moles of water = 18 g x 20 = 360g (iv) From point, 6.022 x 1023 molecules of water = 1 mole = 18g of water 1.2044 x 1025 molecules of water Therefore, points (ii) and (iv) represent 360 g of water.

You might be interested in

DedPeter [7]

Explanation:

- Simple Distillation: its a separation method that can be used when the two or more liquids in the mix have at least 50 degrees of difference between their boiling points.

-Azeotropic distillation: is a technique to break an azeotrope (constant boiling point mixtures), that can't be separated by simple distillation, by adding another component to generate a new azeotrope (between one initial component and the new one added) with lower boiling point.

-Extractive distillation: is a process to separate mixtures with close boiling points by adding a miscible, high boiling or none volatile solvent to increase the relative volatility of the liquids in the mix, this increases the separation factor. It differences from the azeotropic method because it doesn't form an azeotrope.

-Liquid-liquid extraction: is a method to separate compounds based on their relative solubilities in two different immiscible liquids.

After describing all the methods we can conclude that all of them are methods to separate substances based on their physical properties, this is their similarity. The difference between this method is the property it uses to separate (solubility in the case of extraction and boiling point in the case of destinations), the cases in which they bare used (when the liquids difference in boiling points is bigger [simple] or close [attractive and azeotropic]) and the formation of azeotropes (present in azeotropic and absent in extractive).

I hope you find this information useful and interesting! Good luck!

6 0

3 years ago

20.1 g of aluminum and 219 g of chlorine gas react until all of the aluminum metal has been converted to AlCl3. The balanced equ

Romashka-Z-Leto [24]

Answer:

The amount of Cl2 gas left , after the reaction goes to completion is : 139.655 grams

Explanation:

Molar mass : It is the mass in grams present in one mole of the substance.

Moles of the substance is calculated by:

$Moles=\frac{Mass}{Molar\ mass}$

$2Al(s)+3Cl_{2}(g)\leftarrow 2AlCl_{3}(g)$

According to this equation:

2 mole of Al = 3 mole of Cl2 = 2 mole of AlCl3

Molar mass of Al = 27.0 g/mol

Mass of Al = 20.1 gram

Moles of Al present in the reaction :

$Moles=\frac{Mass}{Molar\ mass}$

$Moles=\frac{20.1}{26.98}$

Moles of Al = 0.744

Similarly calculate the moles of Cl2

Molar mass of Cl2 = 71.0 g/mol

Mass = 219 gram

$Moles=\frac{Mass}{Molar\ mass}$

$Moles=\frac{219}{70.98}$

Moles of Cl2 = 3.08 moles

According to equation,

2 mole of Al reacts with = 3 mole of Cl2

1 moles of Al reacts with = 3/2 mole of Cl2

0.744 moles of Al reacts with = 3/2(0.744) moles of Cl2

= 1.116 moles of Cl2

But actually present Cl2 = 3.08 moles

Hence Al is the limiting reagent , and Cl2 is the excess reagent.

The whole Aluminium Al get consumed during the reaction.

The amount of Cl2 in excess = Total Cl2 - Cl2 consumed

Cl2 in excess = 3.08 - 1.116 = 1.964 moles

Cl2 in grams = 1.964 x 70.90 = 139.655 grams

6 0

4 years ago

How many grams of magnesium chloride must be added to 725 mL of water to create a solution with an anion concentration equal to

Sergio [31]

55.2218 grams of magnesium chloride must be added to 725 mL of water to create a solution with an anion concentration equal to 0.800 M.

<h3>How to calculate the no. of moles ? </h3>

To calculate the number of moles from molarity as

$\frac{\text{x moles}\ MgCl_2}{0.725\ \text{L solution}} = \frac{0.8\ \text{moles}\ MgCl_2}{1.0\ \text{L solution}}$

x moles MgCl₂ = $\frac{0.8\ \text{moles}\ MgCl_2}{1.0\ \text{L solution}} \times 0.725\ \text{L solution}$

= 0.58 moles MgCl₂

<h3>What is Molar Mass ?</h3>

Mass of one mole of substance is known as molar mass.

Molar mass of MgCl₂ = Atomic mass of Mg + 2 (Atomic mass of Cl)

= 24.31 + 2 (35.5)

= 95.21

Convert moles to grams

0.58 moles MgCl₂ × $\frac{95.21\ g}{1\ \text{mole}\ MgCl_2}$

= 55.2218 grams

Thus from the above conclusion we can say that 55.2218 grams of magnesium chloride must be added to 725 mL of water to create a solution with an anion concentration equal to 0.800 M.

Learn more about the Molar mass here: brainly.com/question/837939

#SPJ4

5 0

2 years ago

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A soluti

ss7ja [257]

Answer:

1.89 of Sodium Carbonate

3.94 g of Silver Carbonate

2.43 g of Sodium Nitrate

Zero grams of Silver Nitrate

Explanation: